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Greeley [361]
2 years ago
11

8. In how many ways can a committee of four be selected from eight men and seven women if Miss Jones refuses to serve on the sam

e committee as Mr. Smith?
Mathematics
1 answer:
____ [38]2 years ago
4 0
If the exclusion of Miss Jones and Mr Smith serving together was not present, the are 15C4 = 1365 ways of selecting the committee.
Miss Jones can serve on the committee in the following ways:
a) with 3 men
b) with 2 men and another woman
c) with 1 man and 2 other women
d) with 3 other women.
Arrangement d) obviously presents no restrictions.
Arrangement a) has 7C3 ways excluding Mr Smith, and 8C3 ways if Mr Smith was included.
Arrangement b) has 7C2 * 6 ways excluding Mr Smith, and 8C2 * 6 ways if Mr Smith was included.
Arrangement c) has 7 * 6C2 ways excluding Mr Smith, and 8 * 6C2 ways if Mr smith was included.
The reductions in ways caused by the restriction are as follows:
a) 8C3 - 7C3 = 21 ways
b) 6(8C2 - 7C2) = 42 ways
c) 6C2 = 15 ways
The total reduction in the number of ways is: 21 + 42 + 15 = 78.
Therefore the total number of ways of selecting the committee, while observing the restriction, is 1365 - 78 = 1287 ways.
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the width of Yun's area model is 7x units or ( x-2 )units .

<u>Step-by-step explanation:</u>

Here we have , Yun was trying to factor 7x^2-14x.  He found that the greatest common factor of these terms was 7x and made an area model:  What is the width of Yun's area model. Let's find out:

We know that area of rectangle :

⇒ Area = length(width)  .........(1)

Now , According to question we have

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Answer:

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  • pick like terms

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x = -b/2a +   {√( b²-4ac) / 2a }

  • the l.c.m is the same

x = {-b±√( b²-4ac)}/2a

7 0
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