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2 years ago

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Adam and Paul an achieve the sales target of the company in 30 days, Paul and Charles In 40 days while Charles and Adam In 60 da

ys. In how many days can
all three of them achieve the sales target together?

1 answer:

Irina18 [472]2 years ago

5 0

Answer:all three of them achieve the sales target together in 120 days.

Step-by-step explanation:

Given: Adam and Paul an achieve the sales target of the company in 30 days, Paul and Charles In 40 days while Charles and Adam In 60 days.

Then, the number of days taken by all of them to achieve the sales target together = $\dfrac1{30}+\dfrac{1}{40}+\dfrac{1}{60}$

$=\dfrac{1}{120}$ [LCM(30,40,60)=120]

Thus, all three of them achieve the sales target together in 120 days.

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Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How

mixer [17]

To solve this, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial investment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year

For the first 4 years we know that: $P=2350$ , $r= \frac{4.2}{100} =0.042$ , $t=4$ , and since the problem is not specifying how often the interest is communed, we are going to assume it is compounded annually; therefore, $n=1$ . Lest replace those values in our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2350(1+ \frac{0.042}{1} )^{(1)(4)}$
$A=2350(1+0.042)^{4}$
$A=2770.38$

Now, for the next 6 years the intial investment will be the final amount from our previous step, so $P=2770.38$ . We also know that: $r= \frac{4.9}{100} =0.049$ , $t=6$ , and $n=1$ . Lets replace those values in our formula one more time:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2770.38(1+ \frac{0.049}{1})^{(1)(6)$
$A=2770.38(1+0.049)^6$
$A=3691.41$

We can conclude that Collin will have <span>£3691.41 in his account after 10 years.</span>

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2 years ago

CD is a perpendicular bisector of . Which of the following could be the slopes of the two lines if plotted on a coordinate grid?

NISA [10]

Step-by-step explanation:

A is the correct answer of this question

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2 years ago

A gardener wants to plant 122500 trees in his field in such a way that the number of trees in a row is equal to the number of ro

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Given that the gardener wants the number of trees in each raw to be equal to the number of rows, then let the number of in each row be x this means that the number of rows will be x.
Thus the total number of trees will be:
Total=(number of rows)*(number of trees in each row)
hence:
122500=x×x
122500=x²
hence
x=√122500
x=350
thus the number of rows will be 350 and the number of trees in each row will be 350

6 0

2 years ago

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.

zvonat [6]

Answer:

$x=-2.38$

$x=-4.62$

Step-by-step explanation:

The question is $(2x+3)^2+8(2x+3)+11=0$

<em>We let $u=2x+3$ , so the equation becomes:</em>

$u^2+8u+11=0$

Where $a=1, b=8, c=11$

Putting it in the quadratic formula, we have:

<u>Quadratic formula:</u> $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Substituting we have: $\frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }$

<em>We let $u=2x+3$ , so x is:</em>

<em> $u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38$ </em>

<em>and</em>

<em> $u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62$ </em>

The solutions of the equation is $x=-2.38$ (rounded to 2 decimal places), and $x=-4.62$ (rounded to 2 decimal places)

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2 years ago

11. In a certain town the ratio of the number of cars to that of taxis is 15:4. If

Bess [88]

Answer: 645 cars

Step-by-step explanation:

Divide 172 by 4 to find the multiple which is 43 so if 4 was multiplied by 43 to get 172 taxis you must multiply 15 by 43 which gives 645

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2 years ago

Read 2 more answers