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kodGreya [7K]
1 year ago
13

Adam and Paul an achieve the sales target of the company in 30 days, Paul and Charles In 40 days while Charles and Adam In 60 da

ys. In how many days can
all three of them achieve the sales target together?
​
Mathematics
1 answer:
Irina18 [472]1 year ago
5 0

Answer:all three of them achieve the sales target together in 120 days.

Step-by-step explanation:

Given: Adam and Paul an achieve the sales target of the company in 30 days, Paul and Charles In 40 days while Charles and Adam In 60 days.

Then,  the number of days taken by all of them to achieve the sales target together = \dfrac1{30}+\dfrac{1}{40}+\dfrac{1}{60}

=\dfrac{1}{120}     [LCM(30,40,60)=120]

Thus, all three of them achieve the sales target together in 120 days.

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azamat

Answer:

(a) The variance decreases.

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Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

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(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

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\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

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If the sample size is decreased then the standard deviation will increase.

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The standard deviation of the sample mean for <em>n</em> = 784 is:

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Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

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_______________________________

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