A hose with a larger diameter working alone can fill a swimming pool in 9 hours. A hose with a smaller diameter working alone ca n fill a swimming pool in 18 hours. Working together, how long would it take the two hoses to fill the swimming pool?
1 answer:
- The rate of the hose with the large diameter is:
Answer: A). 1/9.
- What is the unknown in the problem?
Answer: C). the time it takes for the hoses working together to fill the pool
-What part of the job does the hose with the large diameter do?
Answer: B). x/9
You might be interested in
Answer:
D
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (y, - x ), thus
C(1, 2 ) → C'(2, - 1 ) → D
Answer:
I) 32.5
ii) 100.1
Step-by-step explanation:
I) 1056.25 = √1056.25
= 32.5
ii) 10020.01= √10020.01
=100.1
Answer:
0.67
Step-by-step explanation:
<u>Solution 1</u>
We can work out the initial number by going backwards from the end:
67/1000= 0.067
0.067*100= 6.7
6.7/10= 0.67
<u>Solution 2</u>
(x*10/100)*1000= 67
x/10*1000= 67
100x= 67
x=67/100
x=0.67
Answer:
the first one is A, the second one is D.
Step-by-step explanation:
For the perimeter you have to multiply by the original dilation number, and for the area, you have to dilate by 2.5
Hope this helps :D
Answer:
Step-by-step explanation:
The best option is for the consultant to remove these data points because they are outliers. Unusual data points which are located far from rest of the data points are known as outliers.
