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elena-14-01-66 [18.8K]
2 years ago
11

Joshua has $34 in his bank account. With his new job, he deposits the same amount each week into the account. After 35 weeks, Jo

shua has $909. What function can find the amount in Joshua's account after w weeks?
Mathematics
1 answer:
mars1129 [50]2 years ago
4 0
<h2>Greetings!</h2>

Answer:

f(x) = 34 + 25w

Step-by-step explanation:

First, we need to find the amount he was paid over the 35 weeks:

909 - 34 = 875

35w = 875

w = 875 / 35 = 25

So every week he is paid $25

The function has to start with 34, as that is the amount already in there, and as w is multiplying by 25, this can be written as 25w

So put these two together:

f(x) = 34 + 25w


<h2>Hope this helps!</h2>
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Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?
Basile [38]

Answer:

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = -b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = -8

It becomes

x = [- 3 ± √3^2 - 4(2 × -8)]/2×2

x = - 3 ± √9 - 4(- 16)]/2×2

x = [- 3 ± √9 + 64]/2×2

x = [- 3 ± √73]/4

x = [- 3 ± 8.544]/4

x = (-3 + 8.544) /4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

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2 years ago
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Choose all sequences of transformations that produce the same image of a given figure.
elena-14-01-66 [18.8K]

<em><u>Your answer: </u></em> a reflection across the y-axis followed by a clockwise rotation 90° about the origin. A clockwise rotation 90° about the origin followed by a reflection across the x-axis. A counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis. A reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin.

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2 years ago
Determine if each of the following sets is a subspace of ℙn, for an appropriate value of n. Type "yes" or "no" for each answer.
xxMikexx [17]

Answer:

1. Yes.

2. No.

3. Yes.

Step-by-step explanation:

Consider the following subsets of Pn given by

1.Let W1 be the set of all polynomials of the form p(t)=at^2, where a is in ℝ.

2.Let W2 be the set of all polynomials of the form p(t)=t^2+a, where a is in ℝ.

3. Let W3 be the set of all polynomials of the form p(t)=at^2+at, where a is in ℝ.

Recall that given a vector space V, a subset W of V is a subspace if the following criteria hold:

- The 0 vector of V is in W.

- Given v,w in W then v+w is in W.

- Given v in W and a a real number, then av is in W.

So, for us to check if the three subsets are a subset of Pn, we must check the three criteria.

- First property:

Note that for W2, for any value of a, the polynomial we get is not the zero polynomial. Hence the first criteria is not met. Then, W2 is not a subspace of Pn.

For W1 and W3, note that if a= 0, then we have p(t) =0, so the zero polynomial is in W1 and W3.

- Second property:

W1. Consider two elements in W1, say, consider a,b different non-zero real numbers and consider the polynomials

p_1 (t) = at^2, p_2(t)=bt^2.

We must check that p_1+p_2(t) is in W1.

Note that

p_1(t)+p_2(t) = at^2+bt^2  = (a+b)t^2

Since a+b is another real number, we have that p1(t)+p2(t) is in W1.

W3. Consider two elements in W3. Say p_1(t) = a(t^2+t), p_2(t)= b(t^2+t). Then

p_1(t) + p_2(t) = a(t^2+t) + b(t^2+t) = (a+b) (t^2+t)

So, again, p1(t)+p2(t) is in W3.

- Third property.

W1. Consider an element in W1 p(t) = at^2and a real scalar b. Then

bp(t) = b(at^2) = (ba)t^2).

Since (ba) is another real scalar, we have that bp(t) is in W1.

W3. Consider an element in W3 p(t) = a(t^2+t)and a real scalar b. Then

bp(t) = b(a(t^2+t)) = (ba)(t^2+t).

Since (ba) is another real scalar, we have that bp(t) is in W3.

After all,

W1 and W3 are subspaces of Pn for n= 2

and W2 is not a subspace of Pn.  

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nevsk [136]

Answer: There are 6 sections of  8\frac{1}{4}\ inches  of rope Mario can cut from the rope .

Step-by-step explanation:

Since we have given that

Length of the rope for the tent = 7 feet

As we know that

1\ feet=12\ inches\\\\7\ feet=12\times 7=84\ inches

Length of rope is used to tie a tarp on top of the tent = 34.5 inches

Remaining length of rope is given by

84-34.5=49.5\ inches

According to question, the remaining rope should be cut into

8\frac{1}{4}\ inches\\\\=\frac{33}{4}\ inches

So, Number of  8\frac{1}{4}\ inches sections of rope Mario can cut from the rope is given by

\frac{49.5}{8\frac{1}{4}}\\\\=\frac{49.5}{\frac{33}{4}}\\\\=\frac{49.5\times 4}{33}\\\\=6

Hence, there are 6 sections of 8\frac{1}{4}\ inches rope Mario can cut from the rope .

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2 years ago
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A. $2.84

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