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2 years ago

Estimate the sum to the nearest tenth: (-2.678) + 4.5 + (-0.68) What is the actual sum?

Mathematics

2 answers:

Llana [10]2 years ago

8 0

Answer:

The answer is 1.142

Step-by-step explanation:

and by the way you could have just used a calculator:)

AURORKA [14]2 years ago

7 0

Answer: the first one is 1.1 and the last one is 1.142

Step-by-step explanation: i just answered the question :))

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What is the value of x in the equation x3=27125 ?

alina1380 [7]

Answer:

x = 30.0462

Step-by-step explanation:

Divide each side by 3 to cancel out the 3 next to x. It should now look like this: x = 30.0462

I hope this helps!

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2 years ago

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

kow [346]

Answer:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.

So 292 - 240 = 52 read below or at eight grade level, and that $n = 292, \pi = \frac{52}{292} = 0.178$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.149$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.28\sqrt{\frac{0.178*0.822}{292}} = 0.207$

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).

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2 years ago

What does the k value do to any function?

lisabon 2012 [21]

Answer:

k moves the value up or down

Step-by-step explanation:

PS: Just listened to the lecture :)

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2 years ago

Marco starts with a population of 10 bacteria that doubles every day for a number of days, d. He writes the expression 10(2d) to

riadik2000 [5.3K]

Answer:

Marco- 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent.

Isabella- 1 is the starting population. 1+0.2=1.2 is the rate at which it grows each day.

Step-by-step explanation:

Marco's equation should be $10(2^{d})$ since the bacteria double each day. 10 is the starting value of the population. 2 is the growth rate of "double each day" with d as an exponent. This will double each day because:

Day 1 is $2^{1}=2$

Day 2 is $2^{2}=4$

Day 3 is $2^{3}=8$

Day 4 is $2^{4}=16$

You'll notice the value doubles each day.

Isabella has a different equation because her population increases by a percentage. We use the simple interest formula to calculate the bacteria's daily increase or interest.

1(1+0.2)d

1 is the starting population.

1+0.2=1.2 is the rate at which it grows each day.

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2 years ago

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Determine the area of squre ABCD with AB=3cm<br>

Travka [436]

Answer:

Area: $9 cm^{2}$