Answer:
The required equation is 
.
Step-by-step explanation:
Consider the provided information.
The Initial value of poster = $ 18
After 1 year amount of increase = $ 20.70
With the rate of 15% = 0.15
Let future value is y and the number of years be x.
Now verify this by substituting x=1 in above equation.
Which is true.
Hence, the required equation is .
Answer:
z = 70
Step-by-step explanation:
Multiply by 25 on both sides:
14/5 = z/25
25(14/5) = (z/25)
25(14/5) = z
Divide:
25(14/5) = z
25(2.8) = z
Multiply:
25(2.8) = z
70 = z
You can factor out 45 out of both 90 and 45.
If we factor out 45, we are given the following...
45(2 + 1) because 45 goes into 90 2 times and 45 once.
Answer:
n = 3
Step-by-step explanation:
-6n - 20 = -2n + 4 (1-3n)
First distribute the 4 (1-3n)
-6n - 20 = -2n + 4 - 12n
Combine like terms on the right side
-6n - 20 = -14n + 4
Get 'n' on one side by adding -6n to both sides
-20 = -8n + 4
Subtract 4 to both sides
-24 = -8n
Divide -8 to both sides
3 = n
Answer:
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.
Step-by-step explanation:
A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.
This polynomial has roots -4, -1, and 5. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.
In this polynomial:
Root -4 has even multiplicity of 4 so it only touches and does not cross through.
Root -1 has odd multiplicity of 3 so crosses through.
Root 5 has even multiplicity of 6 so it only touches and does not cross through.
Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.
To draw this graph, we start from the left in quadrant 3 drawing the curve to -4 on the x-axis to touch it but not cross. We continue back down and curve back around to cross the x-axis at -1. We continue up past -1 and curve back down to 5 on the x-axis. We touch here without crossing and draw the rest of our function heading back up. It should form a sideways s shape.
