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ElenaW [278]
2 years ago
7

Mr.Martinez rents a car for one day.The charge is $36 plus $0.18 per mile.Mr.Martinez has a budget $60.How many miles can he dri

ve
Mathematics
1 answer:
kondor19780726 [428]2 years ago
8 0
1... the wording is a little confusing.
Is the charge $0.18 per mile or is it actually $36.18 per mile?
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Estimate the value of 9.9 squared x 1.79
Helen [10]
9.9^2X1.79
9.9^2=98.01
98.01X1.79=175.4379
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2 years ago
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Gavin likes biking. He never misses a chance to go for a ride when the weather is nice. This week his goal is to bike about 65 t
andreyandreev [35.5K]

Answer:

How far should he ride on each of the four days to reach his goal?

1st day: 8 miles

2nd day: 12 miles

3rd day: 18 miles

4th day: 27 miles

Step-by-step explanation: As the problem says, x is the number of miles he rides on the first day. Let's start off with that.

1st day: x miles

He want to ride 1.5 times as far as he rode the day before... no 1.5 more, but 1.5 <em>times</em> as far as he rode the day before; you would multiply 1.5 with the previous day's length.

2nd day: 1.5x

Then you multiply 1.5 to 1.5x to get the third day's.

3rd day: 2.25x

4th day: 3.375x

----------------------------

Phew! Gavin wants to ride a total of 65 miles over these four days, so if Gavin added all the miles of the four days, he should get 65...

1st+2nd+3rd+4th=65

x+1.5x+2.25x+3.375x=65

8.125x=65

\frac{8.125x}{8.125}=\frac{65}{8.125}

x=8

Yes! Now that we've got the hard part done... substitute 8 for ever single x.

1st day: 8 miles

2nd day: 1.5(8)=12 miles

3rd day: 2.25(8)=18 miles

4th day: 3.375(8)=27 miles

-------------------------

Checking my answer:

Just add the miles!

8+12+18+27=65

65=65

✓

-----------------------

Hope that helps! :D



5 0
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zmey [24]
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</span>3x³ + 2x² - 5x - 8x³ + 2x² =
-5x³ + 4x² - 5x
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2 years ago
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Kirsty counts the number of peas in a sample of pea pods
RoseWind [281]
Mode is most occurring

There is no mode for the peas as there is no score occurring more than once


Median is middle number

So cross of 4 and 5, and 7 and 8

Median is 6


Mean is average


4+5+6+7+8 divided by five


Mean is 6


5 0
2 years ago
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Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian
777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

B=30^o

C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

c=5.61\ units

therefore

The dimensions of the triangle are

A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

4 0
2 years ago
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