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Kruka [31]
2 years ago
10

Cristian, Iris, and Morgan each get an equal share of; of a pizza. Which model represents the fraction of the pizza each person

gets?​

Mathematics
1 answer:
stepladder [879]2 years ago
4 0

Answer:

Each person receives a third of the entire pizza. (Please see image attached below)

Step-by-step explanation:

If Christian, Iris and Morgan receive an equal share of a pizza and a pizza has a value of 1. Then, each person receives a third of 1. That is:

\frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1

Lastly, a graphic representation of the fraction of the pizza each person receives is shown below as attachment.

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A student club holds a meeting. The predicate M(x) denotes whether person x came to the meeting on time. The predicate O(x) refe
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Answer:

a) \exists \, x \in C : O(x) = 0

b) \{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) \{ x \in C: M(x) = 1 \} = C

d) \{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) \exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) \exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

Step-by-step explanation:

  • M(x) = 1 if the person x came to the meeting, and 0 otherwise.
  • O(x) = 1 if the person is an officer of the club and 0 otherwise.
  • D(x) = 1 if the person has paid hid/her club dues and 0 otherwise.

Lets also call C the set given by the members of the club. C is the domain of the functions M, O and D.

a) If someone is not an officer, the there should be at least one value x such that O(x) = 0. This can be expressed by logic expressions this way

\exists \, x \in C : O(x) = 0

b) If all the officers came on time to the meeting, then for a value x such that O(x) = 1, we also have that M(x) = 1. Thus, the set of officers of the Club is contained on the set of persons which came to the meeting on time, this can be written mathematically this way:

\{ x \in C : O(x) = 1 \} \subseteq \{ x \in C : M(x) = 1 \}

c) If everyone was in time for the meeting, then C is equal to the set of persons who came to the meeting on time, or, equivalently, the values x such that M(x) = 1. We can write that this way:

\{ x \in C: M(x) = 1 \} = C

d) If everyone paid their dues or came on time to the meeting, then if we take the set of persons who came to the meeting on time and the set of the persons who paid their dues, then the union of the two sets should be the entire domain C, because otherwise there should be a person that didnt pay nor was it on time. This can be expressed logically this way:

\{ x \in C : D(x) = 1 \} \, \cup \, \{x \in C : M(x) = 1 \} = C

e) If at least one person paid their dues on time and came on time to the meeting, then there should be a value x on C such that M(x) and D(x) are both equal to 1. Therefore

\exists \, x \in C : M(x) = 1 \, \wedge D(x) = 1

f) If there is an officer who did not come on time for the meeting, then there should be a value x in C such that O(x) = 1 (x is an officer), and M(x) = 0. As a result, we have

\exists \, x \in C : O(x) = 1 \, \wedge M(x) = 0

I hope that works for you!

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Since the artist wants to scale his drawing down 3 times, we simply divide the area of his drawing by 3, to get 720/3=240.
The artist wants his drawing area to be 240 in^2
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<em>They are equally likely to occur</em>

Step-by-step explanation:

<u>Probabilities</u>

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We know the probability of it snowing in Eastern Canada tomorrow is 0.40, and we are also aware that the probability of it snowing in Western Canada tomorrow is 2/5. Dividing 2 by 5 we get 0.4. Since both events have the same probability, they are equally likely to occur

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