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Kruka [31]
2 years ago
10

Cristian, Iris, and Morgan each get an equal share of; of a pizza. Which model represents the fraction of the pizza each person

gets?​

Mathematics
1 answer:
stepladder [879]2 years ago
4 0

Answer:

Each person receives a third of the entire pizza. (Please see image attached below)

Step-by-step explanation:

If Christian, Iris and Morgan receive an equal share of a pizza and a pizza has a value of 1. Then, each person receives a third of 1. That is:

\frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1

Lastly, a graphic representation of the fraction of the pizza each person receives is shown below as attachment.

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I think it’s 220 inches
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An 8 foot length of 4 inch wide crown molding costs $16. How much will it cost to buy 40 feet of crown molding?
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The mean of a list of 80 numbers is 230. If four numbers 145,156,210, and 255 are added, what is the mean of the list of numbers
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1 year ago
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Determine the area (in units2) of the region between the two curves by integrating over the x-axis. y = x2 − 24 and y = 1
astra-53 [7]

Answer:

The area of the region between the two curves by integration over the x-axis is 9.9 square units.

Step-by-step explanation:

This case represents a definite integral, in which lower and upper limits are needed, which corresponds to the points where both intersect each other. That is:

x^{2} - 24 = 1

Given that resulting expression is a second order polynomial of the form x^{2} - a^{2}, there are two real and distinct solutions. Roots of the expression are:

x_{1} = -5 and x_{2} = 5.

Now, it is also required to determine which part of the interval (x_{1}, x_{2}) is equal to a number greater than zero (positive). That is:

x^{2} - 24 > 0

x^{2} > 24

x < -4.899 and x > 4.899.

Therefore, exists two sub-intervals: [-5, -4.899] and \left[4.899,5\right]. Besides, x^{2} - 24 > y = 1 in each sub-interval. The definite integral of the region between the two curves over the x-axis is:

A = \int\limits^{-4.899}_{-5} [{1 - (x^{2}-24)]} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} [{1 - (x^{2}-24)]} \, dx

A = \int\limits^{-4.899}_{-5} {25-x^{2}} \, dx + \int\limits^{4.899}_{-4.899} \, dx + \int\limits^{5}_{4.899} {25-x^{2}} \, dx

A = 25\cdot x \right \left|\limits_{-5}^{-4.899} -\frac{1}{3}\cdot x^{3}\left|\limits_{-5}^{-4.899} + x\left|\limits_{-4.899}^{4.899} + 25\cdot x \right \left|\limits_{4.899}^{5} -\frac{1}{3}\cdot x^{3}\left|\limits_{4.899}^{5}

A = 2.525 -2.474+9.798 + 2.525 - 2.474

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The area of the region between the two curves by integration over the x-axis is 9.9 square units.

4 0
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kolezko [41]

Answer:

13 (c)

Step-by-step explanation:

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