Answer:
Step-by-step explanation:
a )
sample mean = sum total of given data / no of data
= 415.35 / 20 = 20.76
To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .
= 20.50 + 20.72 / 2
= 20.61
b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest
(18.92 + 19.25 ..... + 22.43 + 22.85) / 16
= 20.74
c )
We can easily plot the data on number line from 17 to 24
d )
Maximum value of data set = 23.71 and minimum value is 18.04
mean is 20.76 , median is 20.61 and trimmed mean is 20.74
They are between maximum and minimum values of given data . Hence there is no outliers .
For this, we need to find the lowest common multiple of 12 and 15....
common multiples of 12 : 12,24,36,48,60
common multiples of 15 : 15,30,45,60
LCM = 60
the caller that will be the first to win both is the 60th caller
So the problem ask on which of the following choices you had is the points should the banner be attached in the archway and the best answer among the choices will be letter C. (1.5, 4.87) and (3.5, 4.37). I hope this will help you and feel free to ask for more.
Answer:
The whole numbers are 0 and 79.
Step-by-step explanation:
The numbers provided are as follows:

Whole numbers are a set of natural positive numbers and 0. This set basically consists of counting discrete numbers.
Such as: 0, 1, 2, 3, 4, 5....
From the provided set of numbers the whole numbers are:
S = {79 and 0}
Thus, the whole numbers are 0 and 79.