In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
nd leg BC at points P and N respectively. Find: BC:BN
1 answer:
Answer:
BC:BN=8:3
Step-by-step explanation:
ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.
Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD
But, BC= BN+NC
Therefore, BC:BN=(BN+NC):BN
⇒BC:BN=(3+5):3
⇒BC:BN=8:3
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The output value is its thickness. The output value is the y-value.
When you don't fold it all, the thickness will remain the same, which is 2. The ordered pair would be (0, 2).
When you fold it once, the thickness will double from 2 to 4. The ordered pair would be (1,4).
When you fold it a second time, the thickness will double from 4 to 8. The ordered pair would be (2,8).
Fold it one more time, and the thickness will be 16. The ordered pair is (3,16)
Fold it the fourth time, and the thickness doubles. 16 x 2 = 32 The ordered pair is (4, 32)
Fold it the fifth time, and the thickness goes from 32 to 64. The ordered pair is (5,64)
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If we graph that, and we do the vertical line test, then we know this is a function.
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