In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
nd leg BC at points P and N respectively. Find: BC:BN
1 answer:
Answer:
BC:BN=8:3
Step-by-step explanation:
ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.
Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD
But, BC= BN+NC
Therefore, BC:BN=(BN+NC):BN
⇒BC:BN=(3+5):3
⇒BC:BN=8:3
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<u>The given options are:</u>
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.
(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.
(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.
Answer:
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
Step-by-step explanation:
The area of the shaded sector can be determined using the formula:
Therefore, the formula is:
Therefore, the formula is best explained by Option A.
