A little more info please?
Answer:
q = 108-n
Step-by-step explanation:
Given: 108 coins containing only quarters and nickels
q = 108-n
since total number of coins is 108, and n= number of nickels
If you want to know how many of each kind of coin, read on:
First solve the number of quarters and nickels.
If all 108 coins are quarters, the value is 108*0.25 = $27
Since this value exceed the actual by 27-21 = $6,
we replace a number of quarters by nickels.
Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.
So it will take 6/0.2 = 30 replacements.
Therefore there are 108-35 = 78 quarters and 30 nickels.
Answer:
Answer in explanation
Step-by-step explanation:
In this question, we would be examining the validity of some statements on the number π(pi)
π Is a whole number?
This is wrong, π is a fraction of 22 to 7 parts I.e 22/7
π Is double the radius?
This is wrong. It is the diameter that is double the radius
π Is approximately 3.14?
This is correct to an extent. The actual value in decimal is around 3.142857142857143 which makes the 3.14 somehow correct
π represents the ratio of the circumference of the circle to the diameter?
This is correct.
Mathematically, circumference C = π * diameter D
Hence C/D = π
π Is approximately 22/7?
This is correct. This is the ratio used for π
Answer:
y=-4/10x+ 5 or y=-0.4x+5
Step-by-step explanation:
The formula for slope is y=mx+b. The "m" is the slope, the "x" is constant, and "b" is your y-intercept.
1. Figure out your slope:
Easiest way to do this is by using rise/run. You. take your point to the left and count how many spaces up or down it is from the second point, and then repeat that across the x-axis.
2. Determine whether it is positive or negative
A line with a positive slope is going to be angled upward and a line with a negative slope will be angled downward
3. Find the y-intercept
Simply look at the graph and find where the line crosses the y-axis
4. Plug everything into the equation
Once you do Steps 1-3, just plug everything in and you're done! If you have any questions, feel free to ask!
