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brilliants [131]
2 years ago
6

Tranh dives off a 9 m platform. He reaches a maximum height of 9.2 m after 0.26 s. How long does it take him to reach the water

to the nearest hundreth of a second?
Mathematics
1 answer:
777dan777 [17]2 years ago
3 0
He will reach the ground after 2.023 seconds.

To start, write a quadratic equation in vertex form with the given information about the vertex.

y=a(x-2.6)^2+9.2

All that we need to solve for is a. Plug in the point (0, 9) and you will be able to solve for a and write the complete equation.

Now, just use the quadratic formula and you will get 2.023 seconds for when he hits the ground.
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\sin x\ge0 for all x\in[0,\pi], while \cos x>0 for 0 and \cos x for \dfrac\pi2. So you already know that 4\sin x>10\cos x over the second half of the interval.

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