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velikii [3]
1 year ago
8

Conservationists have despaired over destruction of tropical rain forest by logging, clearing, and burning." These words begin a

report on a statistical study of the effects of logging in Borneo. Here are data on the number of tree species in 12 unlogged forest plots and 9 similar plots logged 8 years earlier: Unlogged 22 18 22 20 15 21 13 13 19 13 19 15 Logged 17 4 18 14 18 15 15 10 12 Use the data to give a 90% confidence interval for the difference in mean number of species between unlogged and logged plots. Compute degrees of freedom using the conservative method.Interval: _____ to ______.
Mathematics
1 answer:
Anna [14]1 year ago
4 0

Answer:

[0.841;6.879]

Step-by-step explanation:

Hello!

You have two independent samples:

Sample 1

X₁: tree species in an unlogged plot.

n₁= 12 plots

Unlogged 22 18 22 20 15 21 13 13 19 13 19 15

Sample 2

X₂: tree species in a plot logged 8 years earlier

n₂= 9

Logged 17 4 18 14 18 15 15 10 12

The objective of this experiment is to estimate the difference between the means of the number of species on the unlogged plots and the logged plots. Symbolically: μ₁-μ₂

To be able to estimate the difference between the two population means, I'll assume that both variables have a normal distribution and use a pooled t-statistic for the Confidence interval. (I did a quick F-test for variance homogeneity, population variances are unknown but equal)

The formula is:

(X₁[bar]-X₂[bar])±t_{(n1+n2-2);1-\alpha /2}*(Sₐ√(1/n₁+1/n₂))

Where

sample mean sample 1 X₁[bar]= 17.50

sample mean sample 2 X₂[bar]= 13.64

S₁= 3.53

S₂= 4.50

t_{n1 + n2 - 2;1-\alpha/2} = t_{19;0.95} = 1.729

Sₐ²= <u>(n₁ - 1)S₁² + (n₂ - 1)S₂² </u>= <u>11*(3.53)² + 8*(4.50)² </u>= 15.74

                   n₁+n₂-2                            19

Sₐ= 3.96

Now replace the values in the formula:

(X₁[bar]-X₂[bar])±t_{(n1+n2-2);1-\alpha /2}*(Sₐ√1/n₁+1/n₂)

[(17.50-13.64) ± 1.729*(3.96*√(1/12+1/9))]

[3.86 ± 3.019]

[0.841;6.879]

With a confidence level of 90%, you'd expect that the interval [0.841;6.879] contains the difference between the means of the number of species on the unlogged plots and the logged plots.

I hope it helps!

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What type of triangle has side lengths of 4√5, √145 and 19?
Masja [62]

a, b, c - side lengths (a ≤ b ≤ c)

If a^2+b^2 < c^2, then is Obtuse triangle.

If a^2+b^2=c^2, then is Right triangle.

If a^2+b^2 > c^2, then Acute triangle.

a=4\sqrt5,\ b=\sqrt{145},\ c=19\to a < b < c

Check to see if the sum of the first two sides is greater than the third.

a+b=4\sqrt5+\sqrt{145}\approx9+12=21 > 19=c\\\\CORRECT

a\neq b\neq c\neq a, therefore is Scalene triangle.

a^2=(4\sqrt5)^2=4^2(\sqrt5)^2=16(5)=80\\\\b^2=(\sqrt{145})^2=145\\\\c^2=19^2=361\\\\a^2+b^2=80+145=225 < 361=c^2\\\\a^2+b^2 < c^2

It's Obtuse triangle.

5 0
1 year ago
Ann took a taxi home from the airport. The taxi fare was \$2.10$2.10dollar sign, 2, point, 10 per mile, and she gave the driver
Studentka2010 [4]

Answer:

2.10x+5=49.10

Distance = 21 miles.  

Step-by-step explanation:

Let x be the distance in miles between the airport and Ann's home.

We have been given that Ann took a taxi home from the airport. The taxi fare was $2.10 per mile. So fare for x miles will be 2.10x.

We are also told that she gave the driver a tip of $5. Ann paid a total of $49.10. This means that fare of x miles and tip given to driver equals $49.10. We can represent this information in an equation as:

2.10x+5=49.10

Now let us solve our equation.

2.10x=49.10-5

2.10x=44.10

x=\frac{44.10}{2.10}=21

Therefore, the equation 2.10x+5=49.10 represents the distance in miles between the airport and Ann's home and distance between Ann's home and airport in 21 miles.


3 0
1 year ago
Read 2 more answers
The experimental probability that Kevin will catch a fly ball is equal to 7/8. About what percent of the time will Kevin catch a
Paladinen [302]

Answer:

87.5% percent chance.

Trust me it's right.

6 0
1 year ago
Towns p,q and s are shown Q is 35km due east of P Snis 15km due west of p r is 15km due south of p work out the bearing of r fro
AnnyKZ [126]

Answer:

Step-by-step explanation:

Check attachment for diagram

From the diagram, we can apply Pythagoras theorem to right angle triangle RPS

Then,

Tan θ = opposite / adjacent

Tan θ = 15 / 15

Tan θ = 1

θ = arcTan(1)

θ = 45°

The angle is between the east and south

Then, the bearing of 45°S of east.

The direction is also β

Where

β + θ = 360°

β + 45 = 360°

β = 360 - 45

β = 315°

6 0
2 years ago
A brewery produces cans of beer that are supposed to contain exactly 12 ounces. But owing to the inevitable variation in the fil
MArishka [77]

Answer:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solutio to the problem

Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:

X \sim N(12,0.3)  

Where \mu=12 and \sigma=0.3

For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.

The definition of sample mean is given by:

\bar X = \frac{\sum_{i=1}^n X_i}{n} = \frac{T}{n}

If we solve for the total T we got:

T= n \bar X

For this case then the expected value and variance are given by:

E(T) = n E(\bar X) =n \mu

Var(T) = n^2 Var(\bar X)= n^2 \frac{\sigma^2}{n}= n \sigma^2

And the deviation is just:

Sd(T) = \sqrt{n} \sigma

So then the distribution for the total would be also normal and given by:

T \sim N (\mu = 6*12=72 , \sigma= \sqrt{6} *0.3=0.735)

And we want this probability:

P(T\leq 72)

And we can use the z score formula given by:

z = \frac{x-\mu}{\sigma}

P(T \leq 72) = P(Z< \frac{72-72}{0.735}) = P(Z

6 0
1 year ago
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