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just olya [345]
2 years ago
13

Rachel has 30 pounds of a mixture of candy that sells for $1.00/lb. If lollipops sell for $0.95/lb and caramel candies sell for

$1.10/lb. How many pounds of lollipops are in the mixture?
Mathematics
2 answers:
Butoxors [25]2 years ago
8 0

20 pounds of lollipops. 20 x .95 = 19, 10 x 1.1 = 11. sorry i'm awful at explaining math.

Ivahew [28]2 years ago
5 0

Answer:

20 pounds

Step-by-step explanation:

Let x represent the number of pounds of lollipops and y represent the number of pounds of caramel candies.  The first equation is

x + y = 30,

since the combined numbers of pounds of lollipops and caramel candies.

The lollipops sell for 0.95/lb; this gives us the expression 0.95x.

Caramel candies sell for 1.10/lb; this gives us the expression 1.10y.

Together they make a 30 pound mixture that sells for 1.00/lb; this gives us the expression 30(1.00), which simplifies to 30.

This together gives us the equation

0.95x+1.10y = 30

This gives us the system

\left \{ {{x+y=30} \atop {0.95x+1.10y=30}} \right.

To solve this we will use elimination; we will make the coefficients of x the same by multiplying the top equation by 0.95:

\left \{ {{0.95(x+y=30)} \atop {0.95x+1.10y=30}} \right. \\\\\left \{ {{0.95x+0.95y=28.5} \atop {0.95x+1.10y=30}} \right.

Subtract the second equation from the first:

\left \{ {{0.95x+0.95y=28.5} \atop {-(0.95x+1.10y=30)}} \right. \\\\-0.15y=-1.5

Divide both sides by -0.15:

-0.15y/-0.15 = -1.5/-0.15

y = 10

There are 10 pounds of caramel candies.

Substitute this into the first equation:

x+10 = 30

Subtract 10 from each side:

x+10-10 = 30-10

x = 20

There are 20 pounds of lollipops.

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Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

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b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

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