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qaws [65]
2 years ago
5

Explain how knowing 1+7 helps you find the sum for7+1

Mathematics
1 answer:
ss7ja [257]2 years ago
8 0
1+7 and 7+1 are the same equations. The numbers are just switched around .
Example:
1+2=3
2+1+3

<span>They add up to the same answer no matter where they are placed, therefore knowing 1+7 helps you find the sum of 7+1 (again, because they are the same)  </span>
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The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid. Use the
STALIN [3.7K]
The graph of the parent function f(x<span>) = </span>x2<span> is dashed and the graph of the transformed function </span>g(x) = (x<span> – </span>h)2<span> is solid.

If h=3 the vertex shifts to (3,0). 

If h=-5 the vertex is shifted to (-5,0)

I hope this helps! Sorry no one got back to you in the past few days ):
</span>
3 0
2 years ago
Read 2 more answers
A grocer bought 70 cans of corn. She sold 10 cans that day and 15 cans the next day. How many did she have left?
e-lub [12.9K]

answer

45

step-by-step explanation

total = day1 + day2 + remaining

total = 70

day1 = 10

day2 = 15

plug in values

70 = 10 + 15 + remaining

remaining = 70 - 10 - 15

remaining = 45 cans

3 0
2 years ago
On a piece of paper, graph y = 2x - 4. Then determine which answer matches<br> the graph you drew.
nasty-shy [4]
This is a linear graph where the y-int. Is (0,-4) and the x-int. Is (2,0)

3 0
2 years ago
How many ways are there to put 8 beads of different colors on the vertices of a cube, if rotations of the cube (but not reflecti
Delvig [45]
What is being requested, if I'm not mistaken, is the number of permutations for placing each of the 8 beads on the vertices of the cubes;
In this case, we have 8 different beads and 8 possible locations for each of them;
So the number of permutations is:
8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320
6 0
2 years ago
Read 2 more answers
An attempt to establish a video call via some social media app may fail with probability 0.1. If connection is established and i
xxMikexx [17]

Answer:

(1). y = x ~ Exp (1/3).

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

Step-by-step explanation:

Kindly check the attachment to aid in understanding the solution to the question.

So, from the question, we given the following parameters or information or data;

(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.

(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "

(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."

(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.

(2). Check attachment.

(3). EY = 3(1 - e^-2).

(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.

The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.

8 0
2 years ago
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