Answer:

Step-by-step explanation:
We are given that
Initial value problem
, y(3)=4
Substitute the value 
When t=3 and y=4 then
z=3+4=7

Differentiate z w.r.t t
Then, we get



Integrate on both sides


Substitute t=3 and z=7
Then, we get




Substitute the value of C then we get






The answer
f(x) = 0.7(6)x = <span>f(x) = 0.7(6)^x, and </span><span>g(x) = 0.7(6)–x= </span>g(x) = 0.7(6)^-x=1/<span>0.7(6)^x
so </span>
g(x) =1/<span>0.7(6)^x=1 /</span><span><span>f(x)
</span> the relationship between f and g are </span>g(x) =1 /<span>f(x) or </span><span>g(x) . <span>f(x) = 1</span> </span>
The given points are the vertices of the quadrilateral

By Green's theorem, the line integral is


The arrow is fired with an initial upward velocity of 32ft/s
R = 6t.....subbing in (8,48).....t = 8 and r = 48
48 = 6(8)
48 = 48 (correct)
r = 6t...subbing in (13,78)...t = 13 and r = 78
78 = 6(13)
78 = 78 (correct)
so u have 2 sets of points on this line and they are (8,48) and (13,78)