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nika2105 [10]
2 years ago
13

What is the product? (5r − 4)(r2 − 6r + 4)

Mathematics
2 answers:
Kamila [148]2 years ago
7 0

Answer:

a

Step-by-step explanation:

thank me later

stiks02 [169]2 years ago
5 0
(5r - 4)(r² - 6r + 4)

distributive property of multiplication.

5r(r² - 6r + 4) - 4(r² - 6r + 4)
5r³ - 30r² + 20r - 4r² + 24r - 16

group like terms and simplify.

5r³ - 30r² - 4r² + 20r + 24r - 16

5r³ - 34r² + 44r - 16  Choice A.
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The temperature at a point (x, y) on a flat metal plate is given by T(x, y) = 88/(2 + x2 + y2), where T is measured in °C and x,
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Answer:

D_uT(3,1)=-\frac{44}{9}*\frac{1}{\sqrt{2} } \approx-3.46

Step-by-step explanation:

To find the rate of change of temperature with respect to distance at the point (3, 1) in the x-direction and the y-direction we need to find the Directional Derivative of T(x,y). The definition of the directional derivative is given by:

D_uT(x,y)=T_x(x,y)i+T_y(x,y)j

Where i and j are the rectangular components of a unit vector. In this case, the problem don't give us additional information, so let's asume:

i=\frac{1}{\sqrt{2} }

j=\frac{1}{\sqrt{2} }

So, we need to find the partial derivative with respect to x and y:

In order to do the things easier let's make the next substitution:

u=2+x^2+y^2

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T(x,y)=88*u^{-1}

The partial derivative with respect to x is:

Using the chain rule:

\frac{\partial u}{\partial x}=2x

Hence:

T_x(x,y)=88*(u^{-2})*\frac{\partial u}{\partial x}

Symplying the expression and replacing the value of u:

T_x(x,y)=\frac{-176x}{(2+x^2+y^2)^2}

The partial derivative with respect to y is:

Using the chain rule:

\frac{\partial u}{\partial y}=2y

Hence:

T_y(x,y)=88*(u^{-2})*\frac{\partial u}{\partial y}

Symplying the expression and replacing the value of u:

T_y(x,y)=\frac{-176y}{(2+x^2+y^2)^2}

Therefore:

D_uT(x,y)=(\frac{1}{\sqrt{2} } )*(\frac{-176x}{(2+x^2+y^2)^2} -\frac{176y}{(2+x^2+y^2)^2})

Evaluating the point (3,1)

D_uT(3,1)=(\frac{1}{\sqrt{2} } )*(\frac{-176(3)-176(1)}{(2+3^2+1^2)^2})=(\frac{1}{\sqrt{2} })* (-\frac{704}{144})=(\frac{1}{\sqrt{2} }) ( - \frac{44}{9})\approx -3.46

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