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MA_775_DIABLO [31]
2 years ago
5

A car dealership is having a sale in which customers pay 85% of the retail price for a new vehicle. keith is buying a vehicle wi

th a retail price of $36,000. he negotiates to get 9% off the sale price. how much does keith pay for the vehicle before tax?
Mathematics
1 answer:
mash [69]2 years ago
4 0
First, we calculated the discounted price which would have been paid by Keith. That is the product of 85% and $36,000.
                                      ($36,000) x (85%) = $30,600
Then, after negotiating to pay 9% off the sale price, he will only need to pay 91% of the sale price. The new price would be,
                              ($30600) x (0.91) = $27846
Thus, Keith will only need to pay $27,846. 
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Jack bought a car for $17,500. The car loses $750 in value each year. Which equation represents the situation? Question 9 option
yuradex [85]
If im understanding this correctly, to find the value of the car after x amount of years, the answer would be 17,500 - 750(x)
5 0
1 year ago
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K is the midpoint of segment HL . H has coordinates (1, -7 ) , and K has coordinates(-9, 3 ). Find the coordinates of other end
Andrei [34K]

Answer:

Coordinates of other end point L = ( -19, 13 )

Explanation:

 The mid point of the coordinates (a,b) and (c,d) is given by (\frac{a+c}{2},\frac{b+d}{2})

 Here we have (a,b) = (1,-7) and (\frac{a+c}{2},\frac{b+d}{2}) = (-9,3) , we need to find (c,d).

 \frac{a+c}{2} =-9\\ \\ 1+c=-18\\ \\ c=-19\\\\ \frac{b+d}{2} =3\\ \\ -7+d=6\\ \\ d=13

So coordinates of other end point L = ( -19, 13 )

8 0
2 years ago
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A swimming pool has about 603 cubic feet of water. The pool liner has a small hole and is leaking at a rate of 1.5 cubic feet ea
Readme [11.4K]

Answer:

Ruby’s function notation V(h) describes the volume of the pool after h number of hours. Hours is the independent variable and the total volume is the dependent variable.

Step-by-step explanation:

sample response

3 0
2 years ago
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Which system of equations is inconsistent?
Agata [3.3K]

Answer:

Option A is correct.

The system of equation is inconsistent is;

2x+8y=6

5x+20y=2

Explanation:

* A system of equations is called an inconsistent system, if there is no solution because the lines are parallel.

* If a system has at least one solution, it is said to be consistent .

*A dependent system of equations is when the same line is written in two different forms so that there are infinite solutions.

(A)

2x+8y=6

5x+20y=2

This is inconsistent, because as shown below in the  graph of figure 1 that the lines do not intersect, so the graphs are parallel and there is no solution.

(B)

5x+4y=-14

3x+6y=6

this system of equation is Consistent because it has exactly one solution as shown below in the graph of Figure 2 and also it is independent.

(C)

x+2y=3

4x+6y=5

this system of equation is Consistent because it has exactly one solution as shown below in the graph of Figure 3.

(D)

3x-2y=2

6x-4y=4

this is a consistent system and has an infinite number of solutions, it is dependent because  both equations represent the same line. as shown below in the graph of Figure-4.

Therefore, the only Option A system of equation is inconsistent.



8 0
2 years ago
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G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =
Svetach [21]
Presumably you should be doing this using calculus methods, namely computing the surface integral along \mathbf r(u,v).

But since \mathbf r(u,v) describes a sphere, we can simply recall that the surface area of a sphere of radius a is 4\pi a^2.

In calculus terms, we would first find an expression for the surface element, which is given by

\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv

\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k
\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j
\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k
\implies\left\|\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}\right\|=a^2\sin u

So the area of the surface is

\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u
=-2\pi a^2(\cos\pi-\cos 0)
=-2\pi a^2(-1-1)
=4\pi a^2

as expected.
6 0
2 years ago
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