Question

A meter is 3.37 inches more than a yard. swimmer a swims 100 meters. swimmer b swims 100 yards. approximately how many more feet did swimmer a swim than swimmer b?

Answer 1

Answer:

Swimmer a swims $28\frac{1}{12}\text{ feet}$ more than swimmer b.

Step-by-step explanation:

Given,

The distance covered by swimmer a = 100 meters,

Also, the distance covered by swimmer b = 100 yards,

Difference between the distance covered by a and b = 100 meters - 100 yards

We know that,

1 meter - 1 yards = 3.37 inches,

⇒ 100( 1 meter - 1 yard ) = 337 inches.

⇒ 100 meters - 100 yards = 337 inches

⇒ Difference between the distance covered by a and b = 337 inches,

Since, 1 foot = 12 inches,

⇒ Difference between the distance covered by a and b = $\frac{337}{12}= 28\frac{1}{12}\text{ feet}$

Hence, swimmer a swims $28\frac{1}{12}\text{ feet}$ more than swimmer b.

Answer 2

To determine how many more feet swimmer A swim than B, we first need to convert the measurements given into the same units which would be in feet. We do as follows:

A = 100 m (1 ft / 3.28 m ) = 30.49 ft
B = 100 yds ( 3 ft / 1 yd) = 300 ft

Then, we subtract the value of B to A. 

30.49 - 300 = -269.51 ft ( the negative means that A swim less than B)

Therefore, swimmer A swim 269.51 ft less than swimmer B.