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dolphi86 [110]
1 year ago
14

(1 point) Rework problem 15 in section 2 of Chapter 5 of your textbook about the growing suburb and the declining city using the

following data: Assume that the suburb has a population of 320000 and is growing at a rate of 5000 per year. Assume that the city has a population of 624000 and is declining at a rate of 14000 per year. In how many years will the populations of the suburb and the city be equal
Mathematics
1 answer:
Vanyuwa [196]1 year ago
6 0

Answer:

16 years

Step-by-step explanation:

Let x represent the number of years. The suburb population is growing at a rate of 5000 per year after x years, it can be represented by the equation:

320000 + 5000x

The city population is declining at a rate of 14000 per year after x years, it can be represented by the equation:

624000 - 14000x

The number of years for the city and suburb population to be equal can be gotten from:

320000 + 5000x = 624000 - 14000x

14000x + 5000x = 624000 - 320000

19000x = 304000

x = 304000 / 19000

x = 16

In 16 years the populations of the suburb and the city be equal

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13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas
Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

5+5^{2}=30 (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

5^{1}+5^{2}+5^{3}+...+5^{x}>19000 (II)

Buscamos el valor de x que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000

19530>19000

El valor de x que satisface (II) es x=6.

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro x=6, el número de horas que pasaron son 5 horas (1 menos que el valor de x)

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0
2 years ago
Each of these figures is based on a rectangle whose centre is shown.
NNADVOKAT [17]

The last 2 shapes.

When you rotate both of them 360 degrees only at 180 and back at 360 it looks same.

5 0
2 years ago
Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
1 year ago
Solve for x. −12 = − 3/4 x A) 6 B) 8 C) 12 D) 16
shepuryov [24]

Answer:

D) 16

Step-by-step explanation:

5 0
1 year ago
Read 2 more answers
Suppose that 3% of all athletes are using the endurance-enhancing hormone EPO (you should be able to simply compute the percenta
trapecia [35]

Answer:

Step-by-step explanation:

So there is a 3% probability that an athlete is using EPO .

The probability of showing positive on a test when you've used it is 0.99.

3% x 0.99= 2.97%

The probability of a positive result without EPO is 0.1

97% x 0,1 = 9,7 %

My guess is that 2.97% + 9,7% = 12.67% or 0.1267.

I don't know i may be wrong because you've put as an answer 0.0297 but if you like you may take only the first part of the answer.

6 0
2 years ago
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