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Firdavs [7]
2 years ago
15

A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver

Mathematics
1 answer:
KATRIN_1 [288]2 years ago
5 0

Answer:

The time of a commercial airplane is 280 minutes

Step-by-step explanation:

Let

x -----> the speed of a commercial airplane

y ----> the speed of a jet plane

t -----> the time that a jet airplane takes  from Vancouver to Regina

we know that

The speed is equal to divide the distance by the time

y=2x ----> equation A

<u><em>The speed of a commercial airplane is equal to</em></u>

x=1,730/(t+140) ----> equation B

<u><em>The speed of a jet airplane is equal to</em></u>

y=1,730/t -----> equation C

substitute equation B and equation C in equation A

1,730/t=2(1,730/(t+140))

Solve for t

1/t=(2/(t+140))

t+140=2t

2t-t=140

t=140 minutes

The time of a commercial airplane is

t+140=140+140=280 minutes

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Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola
Artist 52 [7]

Answer:

Tomas added 6 to both sides of the equation instead of subtracting 6.

Step-by-step explanation:

Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation 2x + 6y = 12 to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy.

Given:

2x + 6y = 12

where

x = number of pounds of granola y = number of pounds of walnuts

The correct solution to the problem

x = 3 pounds

2x + 6y = 12

2(3) + 6y = 12

6 + 6y = 12

Subtract 6 from both sides

6 + 6y - 6 = 12 - 6

6y = 6

Divide both sides by 6

y = 6/6

= 1

y = 1 pound

Tomas added 6 to both sides of the equation instead of subtracting 6.

3 0
2 years ago
Read 2 more answers
Solve the system using elimination. x + 2y = –6 3x + 8y = –20 (–4, –1) (–4, 4) (–1, –4) (3, 1)
Orlov [11]

x + 2y =  - 6 >  >  > 3x =  - 18 - 6y
- 18 - 6y + 8y =  - 20 >  >  > 2y =  - 2 >  > y =  - 1
so x=4
6 0
2 years ago
Read 2 more answers
In this problem you will estimate the heat lost by a typical house, assuming that the temperature inside is tin=20∘c and the tem
san4es73 [151]
Step 1:

<span>Calculate the effective thermal conductivity of the wall or ceiling:
</span>
K_eff = [ (13 ÷ 8)(0.12) + (16 - (13 ÷ 8)) × (0.04)] ÷ 16 


K_eff =<span> [ 0.195 + 0.565] </span>÷<span> 16

</span>
K_eff = 0.76 ÷ 16
 

K_eff = 0.0475 W/ (m K) 


Step 2:

Calculate <span>the interior ceiling area:

</span>Area of each of the interior side walls = <span>8.82 m x 8.64 m
                                                                = 76.2 m</span>²

Area of the interior ceiling = 8.64 m × <span>8.64 m
</span>                                             = 74.6 m²

H = - k·A·(Δ - T) ÷ <span>(thickness)
</span>
H = - 0.0475 ÷ (379.45 × 20) ÷  45/8

H = - ( - 0.95 × 379.45 ) ÷<span> 0.1429
</span>
H = <span>2.52 kW </span>
3 0
2 years ago
Shannon rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 13.
Bingel [31]

Answer:

0.

Step-by-step explanation:

Fair dice are dice that have 6 sides, and the probability of rolling a side is the same as rolling another.

Since each die has 6 sides, the most you can get from the two dice are 6 + 6 = 12. Therefore, getting a 13 is impossible. So, there is a probability of 0.

Hope this helps!

4 0
2 years ago
A circle with radius of \greenD{4\,\text{cm}}4cmstart color #1fab54, 4, start text, c, m, end text, end color #1fab54 sits insid
mario62 [17]

Answer:

The area of the shaded region is   329.87\ cm^2

Step-by-step explanation:

<u><em>The correct question is</em></u>

A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?

The shaded region is the area outside the smaller circle and inside the larger circle

we know that

To find out the shaded region subtract the area of the smaller circle from the area of the larger circle

so

A=\pi r_a^{2} -\pi r_b^{2}

simplify

A=\pi (r_a^{2} -r_b^{2})

where

r_a is the radius of the larger circle

r_b is the radius of the smaller circle

we have

r_a=11\ cm\\r_b=4\ cm

substitute

A=\pi (11^{2} -4^{2})

A=\pi (105)\ cm^2

assume

\pi=3.1416

substitute

A=(3.1416)(105)=329.87\ cm^2

7 0
2 years ago
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