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scoray [572]
2 years ago
10

Half of a class took Form A of a test, and half took Form B. Of the students who took form B, 39% passed. What is the probabilit

y that a randomly chosen student took Form B and did not pass?
Mathematics
1 answer:
mr Goodwill [35]2 years ago
5 0

Answer:

NOT VERY LIKELY

Step-by-step explanation:

• 1/2 OF THE CLASS TOOK FORM A

• 1/2 = 50%

• THE CHANCE CANNOT BE OVER 50%

• 39% OUT OF 50% PASSED

• 50% - 39% = 11%

• THE ANSWER IS NOT VERY LIKELY

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Sandra enters a pumpkin growing contest each year. Currently, her pumpkin measures 36 inches in circumference. Using data from p
Arturiano [62]
Hi there.

Using process of elimination & some logic, I believe the answer is:

C) starting size of the pumpkin

I hope this turned out right!

~
5 0
2 years ago
Read 2 more answers
Look at the figure. Which step should be taken next to construct a line through point P perpendicular to BA?
alexira [117]

ANSWER:

C. Place the compass on point A. Open the compass to a point between point P and point B.

EXPLANATION:

A perpendicular is a line that would be at a right angle to line BA.

The next step is to chose a radius that is greater than PB or PA so as to construct the bisector. And this can be done by placing the compass on point A, and open the compass to a point between point P and point B.

Use this radius to draw an arc above and below the line, and repeat the same using B as the center with the same radius. This would form two intersecting arcs above and below line BA. Join the point of intersection of the arcs by a straight line through P. This is the bisector of line BA through point P.

8 0
2 years ago
The quotient of 9 3/4 and 5/8​
suter [353]

Answer:

15.6

Step-by-step explanation:

  1. 9\frac{3}{4} = \frac{39}{4}  
  2. Plug 39/4 in: 39/4 ÷ 5/8
  3. 39/4 ÷ 5/8 = 39/4 × 8/5
  4. 39/4 × 8/5 = 312/20
  5. \frac{312}{20} = 15.6  

I hope this helps!

4 0
2 years ago
Read 2 more answers
Which statement identifies how to show that j(x) = 11.6ex and k(x) = In (StartFraction x Over 11.6 EndFraction) are inverse func
Vadim26 [7]

Answer:

<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>

Step-by-step explanation:

Given the function  j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6}, to show that both equality functions are true, all we need to show is that both  j(k(x)) and k(j(x)) equal x,

For j(k(x));

j(k(x)) = j[(ln x/11.6)]

j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}

j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)

j[(ln x/11.6)] = 11.6 * x/11.6

j[(ln x/11.6)] = x

Hence j[k(x)] = x

Similarly for k[j(x)];

k[j(x)] = k[11.6e^x]

k[11.6e^x] = ln (11.6e^x/11.6)

k[11.6e^x]  = ln(e^x)

exponential function will cancel out the natural logarithm leaving x

k[11.6e^x]  = x

Hence k[j(x)] = x

From the calculations above, it can be seen that j[k(x)] =  k[j(x)]  = x, this shows that the functions j(x) = 11.6e^x and k(x) = ln \dfrac{x}{11.6} are inverse functions.

4 0
2 years ago
Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x
Marta_Voda [28]

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

5 0
2 years ago
Read 2 more answers
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