Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
t = 1.667 s
Step-by-step explanation
The distance traveled since the warning flag in feet is characterized by
d = 30*t^2 + 40*t
Where t is the time in seconds after the car starts accelerating.
We can easily solve this question by plotting the equation using a graphing calculator or plotting tool.
We need to find the time for which the distance d = 150 ft
150 = 30*t^2 + 40*t , t > =0
We can see that this value in the graph is approximately
t = 1.667 s
We can verify
30*(1.667)^2 + 40*(1.667 ) ≈ 150
If you’re saying that 3 pieces costs 2.00 then the answer is 30. 2x10 is the $20.00 so 3x10 = 30 she can buy
Starting with the paints, we have 15$ as our base value. Next, since we add $24.50 for each new canvas bought, 24.5*x=the amount of money for x canvases. Therefore, since 15 is our base value, we have 15+24.5*6=162