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Svetach [21]
1 year ago
10

The BJ Electrical Company needs to hire master electricians and apprentices for a one week project. Master electricians receive

a salary of $750 per week and apprentices receive $350 per week. As part of its contract, the company has agreed to hire at least 30 workers. The local Building Safety Council recommends that each master electrician spend three hours for inspection time during the project. This project should require 25 hours of inspection time. How many of each type of worker should be hired to accomplish the project and still meet the contract safety requirements?
Mathematics
1 answer:
Stells [14]1 year ago
5 0

Answer:

The BJ Electrical Company

The BJ Electrical Company should hire:

8 master electricians and

22 apprentices

in order to accomplish the project and still meet the contract safety requirements.

Step-by-step explanation:

Number of workers needed = 30

Class of workers:

Master electrician, with per week salary = $750 per worker

Apprentices, with per week salary = $350 per worker

Number of inspection hours required from each master electrician = 3 hours

Total inspection hours for the project = 25 hours

Average number of master electricians needed = 25/3 = 8.333 = 8

Number of each type of worker needed:

Master electricians = 8

Apprentices = 22 (30 - 8)

Cost to be incurred for workers:

Master electricians = $6,000 (8 * $750)

Apprentices =               7,700 (22 * $350)

Total labor cost =      $13,700

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By using distance formula :


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Given points = ( 3 , 5.25 ) and ( 3 , - 8.75 )


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On applying formula, we get


Distance = \sqrt{ ( x_{2}-x_{1})^{2}+(y_{2}-y_{1})^2} \\  \\  \\ Distance = \sqrt{ ( 3 - 3 )^{2} + ( - 8.75 - 5.25 )^{2}}  \\ \\ \\ Distance = \sqrt{ ( 0 )^{2}  + ( - 14)^{2}}  \\ \\ \\ Distance = \sqrt{ ( - 14 )^{2}} \\ \\ \\ Distance = \sqrt{ 14^{2}} \:\:\:\:\:\:\:\:\:\:\: \:  \:  \:  \:  \:  \:  \:  \:  | \bold{ ( - 14 )^{2} = 14^{2}}  \\  \\  \\ Distance =  {14}^{2 \times  \frac{1}{2} }  \\  \\  \\  Distance =  {14}^{1}  \\  \\  \\  Distance = 14 \: units








Hence, Option D is correct.
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2 years ago
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Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
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Answer:

4.979044478499338 × 10²⁶

Step-by-step explanation:

Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.

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21 group of mice receiving Drug A  can be selected in ⁶⁰C₂₁ = \frac{60!}{21!39!}

(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug

Drug B 21 mice can be chosen with ³⁹C₂₁ = \frac{39!}{21!18!}

( 39 - 21 = 18)  remained for control with ¹⁸C₁₈ = \frac{18!}{18!0!}

The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = \frac{60!}{21!39!} × \frac{39!}{21!18!} × \frac{18!}{18!0!} = 4.979044478499338 × 10²⁶

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1 year ago
The width of a rectangle is three times its height. If it has an area of 60.75 square feet, what are its dimensions?
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The answer is D my dude don’t over think. Since it’s are multiply your answer choices till you reach 60.75
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A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

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Step-by-step explanation:

Given the side length of a triangle;

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AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

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His 95% confidence interval is (0.065, 0.155).

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