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Svetach [21]
2 years ago
10

The BJ Electrical Company needs to hire master electricians and apprentices for a one week project. Master electricians receive

a salary of $750 per week and apprentices receive $350 per week. As part of its contract, the company has agreed to hire at least 30 workers. The local Building Safety Council recommends that each master electrician spend three hours for inspection time during the project. This project should require 25 hours of inspection time. How many of each type of worker should be hired to accomplish the project and still meet the contract safety requirements?
Mathematics
1 answer:
Stells [14]2 years ago
5 0

Answer:

The BJ Electrical Company

The BJ Electrical Company should hire:

8 master electricians and

22 apprentices

in order to accomplish the project and still meet the contract safety requirements.

Step-by-step explanation:

Number of workers needed = 30

Class of workers:

Master electrician, with per week salary = $750 per worker

Apprentices, with per week salary = $350 per worker

Number of inspection hours required from each master electrician = 3 hours

Total inspection hours for the project = 25 hours

Average number of master electricians needed = 25/3 = 8.333 = 8

Number of each type of worker needed:

Master electricians = 8

Apprentices = 22 (30 - 8)

Cost to be incurred for workers:

Master electricians = $6,000 (8 * $750)

Apprentices =               7,700 (22 * $350)

Total labor cost =      $13,700

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n200080 [17]

Answer:

P(\bar X

P(\bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(2.25,\frac{0.2}{\sqrt{12}})

Solution to the problem

We want this probability:

P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X

P(\bar X

5 0
2 years ago
Regular hexagon ABCDEF has a perimeter of 36. O is the center of the hexagon and of circle O. Circles A, B, C, D, E, and F have
morpeh [17]

Answer:

E. (54\sqrt{3}-27\pi\)

Step-by-step explanation:

I draw the figure described by the statement down there so you can see easily how to solve it.

Notice 3 things:

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- The radius of each circle is half the length of one side of the hexagon. This would mean that the radius of each circle is 3.

- The outer circles have 120°/360° of its area enclose. We get this value because by definition, the hexagon can be divided into 6 regular triangles, each one with every angle equal to 60°. The size of the internal angles of the hexagon will be twice this value.

So, in summary, The area enclosed by the circles is expressed like this:

Acircles = 6 * \frac{120}{360} * π * (r)² + π*r² = 3 * π * r² = 27 π

Now all we need is the area of the regular hexagon, which is simply:

Ahexagon = \frac{1}{2}* p * a

Where p is the perimeter, given by the problem, and a is its apothem, the distance between the center of the hexagon and the middle of one of its sides, that is found by multiplying the length of a side of the hexagon times \frac{\sqrt{3}}{2}.

Ahexagon = \frac{1}{2} * 36 * 6 * \frac{\sqrt{3}}{2} = 54\sqrt{3}.

Then, the area of the shaded area is equal to:

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4 0
2 years ago
TV studio has brought in 9 boy kittens and 6 girl kittens for a cat food commercial. The director is going to choose 9 of these
Amanda [17]

Answer:

probability = 0.2517

Step-by-step explanation:

given data

boy kittens = 9

girl kittens = 6

choose kittens at random = 9

solution

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first we get here total no of probability that is

n(s) = 15 C 9

n(s) = \frac{15!}{9!(15-9)!}  

n(s) =5005

and

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n(3) = \frac{9!}{3!(9-3)!}  

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and

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n(4) = \frac{6!}{4!(6-4)!}  

n(4) = 15

so

total way to chose 5 boy kittens and 4 girl kittens is

total way = 84 ×15  = 1260

so probability that the director chooses 5 boy kittens and 4 girl kittens is

probability = \frac{1260}{5005}  

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6 0
2 years ago
A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 11 feet. The width of
valentina_108 [34]

Answer:

A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

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2 years ago
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laiz [17]

Answer:

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In this, the reason because is more convenient to have four stations is that these are equally distributed and are more stations.

4 0
2 years ago
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