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laila [671]
2 years ago
14

A bar graph titled Album Type Sold per Year has year on the x-axis and number of albums sold on the y-axis. For C D s, in 2008 t

here were 1000 sold; 2009, 800; 2010, 800; 2011, 600; 2012, 400; 2013, 200. For Digital, in 2008 there were 100 sold; 2009, 300; 2010, 300; 2011, 500; 2012, 700; 2013, 900.
Which of these statements is true? Check all that apply.
CDs have a higher mean than digital.
The range of digital is 800.
The median of CDs is 400.
Both have the same interquartile range.
Both have the same median.
Digital’s mean is around 467.
Mathematics
2 answers:
stira [4]2 years ago
8 0

Answer:

True, True, False, True, False, True

Step-by-step explanation:

<u>CDs have a higher mean than digital</u>

<u />

Let's check.  CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33

Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67

CD's mean is higher.  Since you are dividing byt he same number you also could have just added the amount and found which was a larger number.  But yes, this is true.

<u>The range of digital is 800</u>

<u />

The range is the highest number inus the lowest number.  For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800.  So this is true.

<u>The median of CDs is 400. </u>

<u />

The median is the middle value for odd numbers of values, or the average of the two middle values.  6 total values means you have to take the third and fourth and average them.  in CDs the middle values are 800 and 600, the average is 700, so that is what the median is.  this is false.

<u>Both have the same interquartile range. </u>

<u />

Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those.  Then subtract the larger one fromt he smaller one.

IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400

IQR of digital is 700-300 = 400 so yes both are the same.

<u>Both have the same median</u>

<u />

We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400.  So no, the medians are not the same.

<u>Digital’s mean is around 467. </u>

<u />

We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.

slava [35]2 years ago
7 0

Answer:

True, True, False, True, False, True

Step-by-step explanation:

hope it helps UwU

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Kate had 70 brooms; Alisa had 20 more brooms than Kate. What was the ratio of Kate’s brooms to Alisa’s brooms?
Shalnov [3]

Answer:

7:9

Step-by-step explanation:

it was 70:70+90 cuz it was 20 moe than kates broom and if u simpifly that it will be 7:9 and sorry if my grammers bad im also a student lol i hope this helps. :)

4 0
2 years ago
To control pollination, pollen-producing flowers are often removed from the top of corn in a process called detasseling. The hou
____ [38]

Answer: <u>Last option</u>

Z_ {13} = 0.5,\ Z_ {17} = 2.5

Step-by-step explanation:

The z-scores give us information about how many standard deviations from the mean the data are. This difference can be negative, if the data are n deviations to the left of the mean, or it can be positive if the data are n deviations to the right of the mean.

To calculate the Z scores, we calculate the difference between the value of the data and the mean and then divide this difference by the standard deviation.

so  

Z = \frac{x- \mu}{\sigma}.

Where x is the value of the data, μ is the mean and σ is the standard deviation

In this case :

μ = 12 $/h

\sigma = 2 $/h

We need to calculate the Z-scores for x = 17 and x = 13

Then for x = 17:

Z_{17} = \frac{17-12}{2}.

Z_{17} = 2.5

Then for x = 13:

Z_{13} = \frac{13-12}{2}.

Z_{13} = 0.5

Therefore the answer is:

Z_ {13} = 0.5,\ Z_ {17} = 2.5

8 0
2 years ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
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Brrunno [24]

It would be: k+3 = 10

subtracting 3 from both sides,

k+3-3 = 10-3

k=7

6 0
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Which subtraction expression does the number line model show ​
loris [4]

Answer:

13-+4

Step-by-step explanation:

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