Question

If cosine theta almost-equals 0.3090, which of the following represents approximate values of sine theta and tangent theta, for 0 degrees less-than theta less-than 90 degrees?
sine theta almost-equals 0.9511; tangent theta almost equals 0.3249
sine theta almost-equals 0.9511; tangent theta almost equals 3.0780
sine theta almost-equals 3.2362; tangent theta almost-equals 0.0955
sine theta almost-equals 3.2362; tangent theta almost-equals 10.4731

Answer 1

Answer:

answer is B on edge

Step-by-step explanation:

hope this helps!!!

Answer 2

Answer:

$\sin \theta = 0.9511$ and $\tan \theta = 3.078$

Step-by-step explanation:

Given that, $\cos \theta = 0.309$.

Now, we have to calculate the values of $\sin \theta$ and $\tan \theta$.

We know the identity that, $\sin^{2}\theta + \cos^{2}\theta = 1$

So, $\sin \theta = \sqrt{1 + \cos^{2}\theta} = \sqrt{1 - (0.309)^{2}} = 0.9511$ {Since $0 \leq \theta \leq 90^{\circ}$}

Now, $\sec \theta = \frac{1}{\cos\theta} = \frac{1}{0.309} = 3.236$

Then, we know the identity, $\sec^{2}\theta - \tan^{2}\theta = 1$

So, $\tan \theta = \sqrt{\sec^{2}\theta - 1} = \sqrt{(3.236)^{2} - 1} = 3.078$ (Answer) {Since $0 \leq \theta \leq 90^{\circ}$}