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siniylev [52]
2 years ago
11

Mike is installing weatherstripping around a window that measures 3.5 ft x 4.5 ft. How much weatherstripping will he need?

Mathematics
2 answers:
marishachu [46]2 years ago
7 0

Answer:

16\ ft

Step-by-step explanation:

To find how much weatherstripping will Mike need, calculate the perimeter of the window

so

The perimeter of a rectangular shape is equal to

P=2(b+h)

we have that

b=3.5\ ft, h=4.5\ ft

substitute in the formula

P=2(3.5+4.5)=16\ ft


Juli2301 [7.4K]2 years ago
3 0
3.5 * 2 + 4.5* 2 = 16
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Shishir bought 4000 orange at 70 paisa each. But 400 of them were rotten. He sold 2000 oranges at 90 paisa each.If he plans to m
Ipatiy [6.2K]

Answer:

He needs to sell the rest of the oranges at 75 paisa each.

Step-by-step explanation:

Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

Note: 1 rupees = 100 paisa

Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

2000×0.90 rupees = 1800 rupees

The number of oranges now Shishir have:

4000 - 2000 - 400 = 1600

He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

2800 rupees + 200 rupees = 3000 rupees

He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:

3000 rupees - 1800 rupees = 1200 rupees

Therefore, the cost of one orange is:

1600 oranges = 1200 rupees

1 orange = 1200/1600 rupees

1 orange = 0.75 rupees

Hence, he needs to sell the rest of the oranges at 75 paisa each.

4 0
2 years ago
The diagram shows a square (6x -1)cm (4x+6)cm find the length of the side of the square
sammy [17]

Answer:

3.5 cm

Step-by-step explanation:

6x-1=4x+6

6x-4x=1+6

2x=7

x=7÷2

x=3.5

I hope my answer will help you and i guess it's correct

7 0
2 years ago
An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to
Serhud [2]

Answer:

either of ...

• quadrant 1 only

• quadrant 1 and 4 only

Step-by-step explanation:

Time since the storm started is always positive. The values of x are positive in quadrants 1 and 4.

Temperatures in a blizzard are not always terribly cold. Some of the coldest snowstorms on record have temperatures in the range of +5 °F to +18 °F. These values are negative temperatures on the Celsius scale, so the quadrant used for plotting them will depend on the temperature scale you choose.

While temperatures in Alaska can be well below zero (on either the F or C temperature scales), the air usually has to warm up to the range indicated above before it can snow. US temperatures are generally reported using the Fahrenheit scale, but weather records are often kept using the Celsius scale.

I would be inclined to choose "Quadrant 1 and 4 only", but arguments can be made for "1 only" and "4 only" as suggested above.

8 0
2 years ago
Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 26, the length of A C is 10, and the leng
ExtremeBDS [4]

Answer:

<h2>The right option is twelve-fifths</h2>

Step-by-step explanation:

Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

Tan (A) = opp/adj

Taken BC as opposite side since it is facing angle A directly and AC as the adjacent;

tan(A) = BC/AC

tan(A) = 24/10

tan(A) = 12/5

The right option is therefore twelve-fifths

7 0
2 years ago
Read 2 more answers
Which oh the following are among the five basic postulates of Euclidean geometry
igomit [66]

1. A straight line segment can be drawn joining any two points.

2. Any straight line segment can be extended indefinitely in a straight line.

3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.

4. All right angles are congruent.

5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.

8 0
2 years ago
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