Answer:
The sides of ∆ABC are 30 units, 40 units, and 60 units long.
The perimeter will be = 
units
Given is that ∆ABC and ∆XYZ are similar and the corresponding sides of ∆XYZ are 'r' times as long as the sides of ∆ABC.
So, perimeter of ∆XYZ will be : 
units.
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The area of ∆ABC is n square units, so area of ∆XYZ will be :
= 
= 
square units.
So by definition, area is equal to the length (x) times the width (y). The area of the square mat is = x × y, or xy
If the area of<span> the rectangular mat is twice that of the square mat, the area of the rectangular mat would have to be = 2 </span>× x × y<span>
This can be written as 2x </span>× y, making the length of the rectangular mat twice that of the square mat's length, and the width the same as the square mat's width.<span>
</span>
Answer:
there is no question below therefore, we can't answer it
The parent function is f(x) = x^3
The domain are all x values (-infinity, infinity)
The range are all y values (-infinity, infinity)
We have the following equation:
If we graph this equation we realize that in fact this is an ellipse with
major axis matching the y-axis. So we can recognize these characteristics:
1. Center of the ellipse: The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
2. Length of major axis:
The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>
3. Length of minor axis:
The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:
4. Foci:Let's find c as follows:
Then the foci are:
