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marin [14]
2 years ago
12

A sociologist wishes to see if it is true that for a certain group of professional women, the average age at which they have the

ir first child is 28.6 years. A random sample of 36 women is selected, and their ages at the birth of their first child are recorded. At α = 0.05, does the evidence refute the sociologist’s assertion? Assume σ = 4.18.
Mathematics
1 answer:
Vadim26 [7]2 years ago
3 0

Answer:

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

Step-by-step explanation:

The explanation of given question is described below:

Here, the test of hypothesis states that

H_o : Mean = 28.6

H_a : Mean\ which\ is\ not\ equals\ 28.6

The test statistic is

Z = \frac{(\bar X - Mean)}{\frac{Population\ standard\ deviation}{vn} }

Z = \frac{(30.06 - 28.6)}{\frac{4.18}{6} }

= 2.1

According to the given data α = 0.05,

So, the major value is

IZ(0.025)I = 1.96

(refer to the standard normal table) .

Finally

Z = 2.1\ is\ higher\ than\ 1.96, we\ reject\ H_o

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Is "8.313313331..." a rational or irrational number
Snowcat [4.5K]

Answer:

Irrational

Step-by-step explanation:

Repeating decimals are rational.  Nonrepeating are irrational.

This is a nonrepeating decimal.  First you have one 3, then two 3s, then three 3s.  It's not a repeating pattern.  So it's an irrational number.

7 0
2 years ago
Please help me!!!!!!!!!!
bezimeni [28]
9.2 x 13.8 = 126.96, now usually to get the area of a triangle we would half this but because we have two of the same triangle we would then have to double it again so they cancel each other out. We then do 6.9 x 9.2 which equals 63.48 and again we have two of the same triangle so no need to half it. So we add the two totals of 126.96 and 63.48 together to get 190.44.
4 0
1 year ago
According to a 2011 report by the United States Department of Labor, civilian Americans spend 2.75 hours per day watching televi
marusya05 [52]

Answer:

Step-by-step explanation:

Confidence interval is written in the form, sample mean ± margin of error

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Therefore, the INVALID interpretations of the 95% confidence interval are

A. About 95% of all Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

B. There is a 95% chance that, on average, Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

D. In the long run, 95% of the sample means will be between 2.619 and 3.401 hours.

E. None of the above.

3 0
1 year ago
I am a factor of 18.the other factor is 9.what number am i?
Liula [17]
The answer to this question is 2

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klemol [59]
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