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2 years ago

14

A square has sides with a length of 5.8 inches. what is the effect on the perimeter of this square if the lengths of the sides a

re tripled?

1 answer:

Alla [95]2 years ago

4 0

By definition, the perimeter of a square is given by:

$P = 4L$

Where,

L: length of the sides of the square.

When the sides of the square are tripled, the equation changes as follows:

$P '= 4 (3L)$

Then, rewriting the equation we have:

$P '= 3 (4L)$

$P '= 3P$

Where,

P: perimeter of the original square.

Therefore, we can conclude that the perimeter is tripled.

Answer:

The perimeter of the square is tripled.

$P '= 3P$

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<h2>Pls give brainliest.</h2>

Answer:

I only know two right answers.

A: The center of dilation is point C.

C: It is an enlargement.

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Step-by-step explanation:

These two answers are correct because When you look in the center you see a C.

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1 year ago

The aquarium at Sea Critters Depot contains 140 fish. Eighty of these fish are green swordtails (44 female and 36 male) and 60 a

maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

$\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}$

$\text{P(green swordtail)}=\dfrac{80}{140}$

$\text{P(green swordtail)}=\dfrac{4}{7}$

Therefore, the probability that the selected fish is a green swordtail is $\dfrac{4}{7}.$

B. We have to find the probability that the selected fish is male.

$\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}$

$\text{P(Male fish)}=\dfrac{36+24}{140}$

$\text{P(Male fish)}=\dfrac{60}{140}$

$\text{P(Male fish)}=\dfrac{3}{7}$

Therefore, the probability that the selected fish is a male, is $\dfrac{3}{7}.$

C. We have to find the probability that the selected fish is a male green swordtail.

$\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}$

$\text{P(Male green swordtail)}=\dfrac{36}{140}$

$\text{P(Male green swordtail)}=\dfrac{9}{35}$

Therefore, probability that the selected fish is a male green swordtail is $\dfrac{9}{35}.$

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

$\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}$

$\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}$

$\text{P(Male or green swordtail)}=\dfrac{96}{140}$

$\text{P(Male or green swordtail)}=\dfrac{24}{35}$

Therefore, the probability the selected fish is either a male or a green swordtail is $\dfrac{24}{35}.$

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2 years ago

The library is 1.75 miles directly north from the school. The park is 0.6 miles directly south of the school. How far away is th

Kryger [21]

Answer:

2.35 miles

Step-by-step explanation:

Please find the attachment for visual understanding.

We are told that the library is 1.75 miles directly north from the school and the park is 0.6 miles directly south of the school.

To find distance between library and park we will add distance of library from school to the distance of park from school.

$(1.75+0.6)\text{ miles}=2.35\text{ miles}$

Therefore, library is 2.35 miles away from park.

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2 years ago

Which statements are true about these lines? Select three<br> options.

gayaneshka [121]

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1 year ago

9. Liz works at the ballpark selling bottled

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Answer:

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First do a random amount and move closer to the answer by changing the amount of bottles

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50/5=10

81/3=27

37 bottles so Liz sold 10 big bottles and 27 small bottles.

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2 years ago