Answer:
The 90% confidence interval using Student's t-distribution is (9.22, 11.61).
Step-by-step explanation:
Since we know the sample is not big enough to use a z-distribution, we use student's t-distribution instead.
The formula to calculate the confidence interval is given by:
Where:
is the sample's mean,
is t-score with n-1 degrees of freedom,
is the standard error,
is the sample's size.
This part of the equation is called margin of error:
We know that:
degrees of freedom
Replacing in the formula with the corresponding values we obtain the confidence interval:

Answer:
248.40
Step-by-step explanation:
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Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
The m in y=mx+b stands for the slope of the line
Hope this helps!
A logistic differential equation can be written as follows:
![\frac{dP}{dt} = rP[1- \frac{P}{K}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdt%7D%20%3D%20rP%5B1-%20%5Cfrac%7BP%7D%7BK%7D%5D%20)
where r = growth parameter and K = carrying parameter.
In order to write you equation in this form, you have to regroup 2:
![\frac{dP}{dt} = 2P[1- \frac{P}{10000}]](https://tex.z-dn.net/?f=%20%5Cfrac%7BdP%7D%7Bdt%7D%20%3D%202P%5B1-%20%5Cfrac%7BP%7D%7B10000%7D%5D%20)
Therefore, in you case r = 2 and K = 10000
To solve the logistic differential equation you need to solve:
![\int { \frac{1}{[P(1- \frac{P}{K})] } } \, dP = \int {r} \, dt](https://tex.z-dn.net/?f=%20%5Cint%20%7B%20%5Cfrac%7B1%7D%7B%5BP%281-%20%5Cfrac%7BP%7D%7BK%7D%29%5D%20%7D%20%7D%20%5C%2C%20dP%20%3D%20%20%5Cint%20%7Br%7D%20%5C%2C%20dt%20%20)
The soution will be:
P(t) =

where P(0) is the initial population.
In your case, you'll have:
P(t) = <span>

Now you have to calculate the limit of P(t).
We know that
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hence,

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