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UNO [17]
1 year ago
10

Please help me!!!!!!!!!!

Mathematics
1 answer:
bezimeni [28]1 year ago
4 0
9.2 x 13.8 = 126.96, now usually to get the area of a triangle we would half this but because we have two of the same triangle we would then have to double it again so they cancel each other out. We then do 6.9 x 9.2 which equals 63.48 and again we have two of the same triangle so no need to half it. So we add the two totals of 126.96 and 63.48 together to get 190.44.
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Vertex A in quadrilateral ABCD lies at (-3, 2). If you rotate ABCD 180° clockwise about the origin, what will be the coordinates
Marysya12 [62]
I think it might be B hope I’m right
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2 years ago
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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
1 year ago
Which is the graph of the system x + 3y > –3 and y < One-halfx + 1?
fenix001 [56]

Answer: THE GRAPH IS ATTACHED.

Step-by-step explanation:

We know that the lines are:

x + 3y=-3

y = \frac{1}{2} x + 1

Solving for "y" from the first line, we get:

3y=-x-3\\\\y=-\frac{x}{3}-1

In order to graph them, we can find the x-intercepts and the y-intercepts.

For the line x + 3y=-3 the x-intercepts is:

0=-\frac{x}{3}-1\\\\(1)(-3)=x\\\\x=-3

And the y-intercept is:

y=-\frac{0}{3}-1\\\\y=-1

For the line y=\frac{1}{2} x + 1 the x-intercepts is:

0=\frac{1}{2} x + 1\\\\-1(2)=x\\\\x=-2

And the y-intercept is:

y=\frac{1}{2} (0)+ 1\\\\y=1

 Now we can graph both lines, as you can observe in the image attached (The symbols and > indicates that the lines must be dashed).

By definition, the solution is the intersection region of all the solutions in the system of inequalities.

6 0
1 year ago
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A balance scale was in perfect balance when Jane placed a box of candy on one pane of the balance and 3/4 of the same sized cand
dangina [55]

Answer:

Step-by-step explanation:

i'm pretty sure that you will have to add it.

so, when we add two fractions such as 3/4 + 3/4, we make sure that the denominators (the bottom numbers) are the same and then we simply add the numerators (the  top numbers).

in this problem, the denominators are the same so we will simply add 3+3 which equals to 6/4. the denominator will remain the same.

               <em>answer:</em>

                      3/4 + 3/4    =   6/4

<u>i hope this is helpful. </u>

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Oliga [24]
His equation could be written in quadratic form, which is ax^2+bx=c                     


7 0
1 year ago
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