This might be a problem considering he would have no money left considering unless I made a mistake all the numbers add up to 1,400 so considering this he won't have money to spend if he get in a situation that he needs to spend
(I am not 100% sure this is the answer you are looking for)
Answer:
Option B. 
Step-by-step explanation:
we have

Solve for w
That means ----> isolate the variable w
Multiply by 5 both sides to remove the fraction

subtract 8 both sides


Rewrite

Answer:
The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.
Step-by-step explanation:
Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

In the first year the value of the printer is:

On the second year the value of the printer is:

On the third year the value of the printer is:

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.
Answer:
2.12 ft above ground level
Step-by-step explanation:
Volume of the cylindrical tank is 36*π
Tank is filled to half its capacity, that means tank is filled 18*π, and level of water is 4 feet, then the height of the cylinder is 8 feet
With the above information we can calculate the radius of the base of the cylinder, according to
V = 36*π = π*r²*h ⇒ 36 = r²*h ⇒ 36/8 = r² ⇒ r = 2.12 ft
Then the radius of the base is 2.12 ft
When the cylindrical tank is place on its side, the level of water inside have to be 2.12 ft above ground level. That is the level of half its capacity