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2 years ago

7

Miguel created the ratio table below to show how he uses the money he earns at work. How much money will he save if he earns 120

.00?

2 answers:

Dmitrij [34]2 years ago

5 0

Answer:

$90.00

Step-by-step explanation:

loris [4]2 years ago

3 0

Answer:

The money he will save if he earns $120.00 is <u> $90.00</u>.

Step-by-step explanation:

Given:

In the figure is the ratio of the savings and the earnings.

Now, to find out that how much savings will be if Miguel earns $120.00.

We need to get the percentage of the ratio of the earning and saving.

So, according to the table:

If he earns $10.00 then he saves $7.50.

$\frac{7.50}{10}\times 100$

$=0.75\times 100$

$=75$

So, if Miguel earns $10.00 he save the 75% of it.

If he earns $50.00 then he saves $37.50.

As we calculate the percentage as the above process then the saving is 75% of the earning.

And, if he earns $150.00 and save $112.50 then it is also the 75% of the earning as mentioned above.

Now, to find the saving of the earning $120.00.

So, it will be 75% of the earning as we observe in the above case:

75% of $120.00

$\frac{75}{100}\times 120$

$=0.75\times 120$

$=90$

Therefore, the money he will save if he earns $120.00 is <u> $90.00</u>.

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A fly trapped inside a cubical box with side length 1 meter decides to relieve its boredom by visiting each corner of the box. I

Lelu [443]

Answer:

(4 √ 3 + 4 √2 ) m

Step-by-step explanation:

The insect can travel from one corner directly to opposite corner in four different ways

each can be calculated using Pythagoras theorem

firstly for one face we need to calculate the diagonal

H² = 1² + 1² = 2

H = √2

then we calculate the diagonal opposite a corner

for example

A to H where A is at the bottom and H opposite A in another plane at the top in the cubical box

(Interior diagonal for A to H)² = √2² + 1² = 3

Interior diagonal from A to H = √ 3

there are four such corners, the fly will travel 4 √ 3 and it could also go 4 √2 diagonally to the the other corners

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2 years ago

Wyatt's dog is tethered to a post in his yard. If the rope tied to the dog is 12 feet long, how many square yards does the dog h

adelina 88 [10]

So we start with the area of a circle equation
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2 years ago

Read 2 more answers

Triangle J L N is cut by line segment K M. LIne segment K M goes from side J L to side L N. The length of J K is 10, the length

MrMuchimi

Answer:

D. Yes, because StartFraction 16 Over 10 EndFraction equals StartFraction 24 Over 15 EndFraction.

Step-by-step explanation:

When two line are parallel, they do not meet even with continuous extension of their length.

In the given triangle JLN, line segment KM would be parallel to side JN if;

$\frac{KL}{JK}$ = $\frac{LM}{MN}$

Given that: KL = 16, JK = 10, LM = 24 and MN = 15.

⇒ $\frac{16}{10}$ = $\frac{24}{15}$

$\frac{8}{5}$ = $\frac{8}{5}$

Therefore, since the ratios are the same then KM ∥ JN. So that the statement; Yes, because $\frac{16}{10}$ equals $\frac{24}{15}$ is correct.

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2 years ago

An agricultural sprinkler distributes water in a circular pattern of radius 120 ft. It supplies water to a depth of e−r feet per

STatiana [176]

Answer:

a) $\bf 2\pi(1-e^{-120})\;(ft)^3$ cubic feet per hour

b) $\bf \frac{2(1-e^{-R})}{R^2}$ cubic feet per hour per squared foot

Step-by-step explanation:

The region inside the circle R in polar coordinates can be written as

$\bf R=\left \{ (r,\theta)|0\leq r\leq R,0\leq \theta\leq 2\pi \right \}$

(a) If 0 < R ≤ 120, what is the total amount of water supplied per hour to the region inside the circle of radius R centered at the sprinkler?

$\bf \int_{0}^{120}\int_{0}^{2\pi}e^{-r}drd\theta$

Since the exponential is a continuous function we can split the integral

$\bf \int_{0}^{120}\int_{0}^{2\pi}e^{-r}drd\theta=\int_{0}^{120}e^{-r}dr\int_{0}^{2\pi}d\theta=\\(1-e^{-120})2\pi$

and the total amount of water supplied per hour to the region inside the circle of radius R centered at the sprinkler equals

$\bf \boxed{2\pi(1-e^{-120})\;(ft)^3}$

(b) Determine an expression for the average amount of water per hour per square foot supplied to the region inside the circle of radius R.

This would the total amount of water received by the region inside R divided by the area of the region

$\bf \frac{1}{\pi R^2}\left (\int_{0}^{R}\int_{0}^{2\pi}e^{-r}drd\theta\right )=\frac{2\pi(1-e^{-R})}{\pi R^2}=\frac{2(1-e^{-R})}{R^2}$

and the average amount of water per hour per square foot supplied to the region inside the circle of radius R is

$\bf \boxed{\frac{2(1-e^{-R})}{R^2}}$

cubic feet per hour per square foot.

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2 years ago

Which description fits the graph of x > 4?

tester [92]

<u>Given</u>:

The given inequality is $x>4$

We need to determine the graph that fits the inequality.

<u>Graph of the inequality:</u>

The inequality means that x is greater than 4. This means that the end value 4 is not included.

To graph the inequality " > " a dashed line is used.

The inequality does not contain any y - value in it.

Hence, it has only one vertical line at $x=4$ and is shaded for all values of x greater than 4.

Therefore, the graph that fits the inequality $x>4$ is a vertical dashed line, shaded to the right of the line.

Thus, Option d is the correct answer.

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2 years ago