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Katyanochek1 [597]
2 years ago
11

The electromagnetic waves with the shortest wavelengths and the highest frequencies are called

Mathematics
1 answer:
Norma-Jean [14]2 years ago
4 0
Radio waves I believe
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What is the greatest common factor of x2y and xy2 ?
Bond [772]
GCF of :2xy and 2xy
   

2(x+y)

5 0
2 years ago
8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
denpristay [2]

Answer:

38

Step-by-step explanation:

We can express the 8th term as x and the 12th term as y.

This would mean that 8x=12y

Because the common difference between terms is -2 and term 8 and term 12 are 4 terms apart, this means that the 12th term is 8 less than the 8th term, so x-8=y

Now we can use this to substitute y with x in the first equation. This would give us:

8x=12(x-8)

Which we can expand and solve:

8x=12x-96

-4x=-96

Therefore x=24

This means the 8th term is 24 and the 12th term is 16 (24-8).

To test if this is correct we can do:

8x24=12x16

Which indeed are equal, both sides multiply to 192.

Now that we have our 8th term, we can find the 1st term, which is 7 terms away, therefore we just add 14 to the 8th term 24. (7x2=14)

24+14=38.

The first term is 38.

Hope this helped!

3 0
2 years ago
Which function could be shown in the graph below
defon

Answer:

quintic function

Step-by-step explanation:

3 0
2 years ago
Mr. Ramirez purchased 20 concert tickets for a total of $225. The concert tickets cost $15 for adults and $10 for children under
sveticcg [70]

Answer:

$225 = $15 a + $ 10 c

Step-by-step explanation:

Given,

Total price = $225

Cost of concert ticket for adults= $15

Cost of concert ticket for children = $10

System of equation to represent scenario

a is variable for adult

c is variable for children

Now,

Total price =  $15 a + $ 10 c

$225 = $15 a + $ 10 c

5 0
2 years ago
The vertex of this parabola is at (2,-4). When the y value is -3, the x-value is
marusya05 [52]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} h=2\\ k=-4 \end{cases}\implies y=a(x-2)^2-4 \\\\\\ \textit{we also know that } \begin{cases} y = -3\\ x = -3 \end{cases}\implies -3=a(-3-2)^2-4\implies 1=a(-5)^2 \\\\\\ 1=25a\implies \boxed{\cfrac{1}{25}=a}

4 0
2 years ago
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