Hey there!
Before you start solving anything, you need to identify which situation you want to call event A and which you want to call event B. I usually just do it in the order of the events as they're given to me in the question, so:
A = S<span>tudent participates in student council
B = S</span><span>tudent participates in after school sports
Any problems that contain the word "given" in the question portion will want you to refer to </span>P(A | B)<span> = P(</span>A ∩ B)/P(B). P(A | B) literally means "probability of event A, given that event B has occurred." P(A ∩ B) is the probability of event A and B happening, and P(B) is just the probability of event B happening. We've been given all of that, so:
P(A | B) = P(A ∩ B)/P(B)
P(A | B) = 11% / 62%
P(A | B) = 0.11 / 0.62
P(A | B) = 0.18
There will be about an 18% chance that <span>a student participates in student council, given that the student participates in after school sports.
Hope this helped you out! :-)</span>
E+7 means 10^+7
basically move the decimal place 7 placs to right so it would be aprox
38200000.0
<h2>
Therefore he took 40 gram of
type solution and 10 gram of
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of
type solution
and he took (50-x) gram of
type solution.
Total amount of alcohol =
gram
Total amount of solution = 50 gram
According to problem
⇔![\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Bx%5Ctimes%5Cfrac%7B13%7D%7B100%7D%5D%20%2B%5B%2850%20-x%29%20%5Ctimes%5Cfrac%7B18%7D%7B100%7D%20%5D%7D%7B50%7D%3D%20%5Cfrac%7B14%7D%7B100%7D)
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of
type solution and (50 -40)gram = 10 gram of
type solution.