Answer: The total purchase price is $ 29,032
Step-by-step explanation:
Hi, to solve this problem you have to solve the percentages of each taxes first.
So :
- state taxes =$24,500 × 5.5% = $1,347.5
- federal tax = $24,500 × 13% = $3,185
The next step is adding the taxes results to the speedboat cost.
so:
speedboat = $24,500
speedboat + taxes = $24,500 + $1,347.5 +$3,185 = $29,032
The total purchse price for the speedboat is $29,032.
Hello there! So, let's do this a bit at a time. Mike's Bikes sells a bike for $300, but gives a 25% discount for any bike in the store. To find out how much he would pay for the bike, multiply 300 by 75% (0.75). This is because you are still paying 75% of the original price for that bike. When you do, you get 225. That's $225 for the bike at Mike's Bikes. Now, the one at Cycle Center sells a bike for $275, but gives a rebate of $40 after purchasing the bike. A rebate is basically a refund: you get money paid back to you. In this case, we would subtract 40 from 275, because you're basically getting paid back some of what you did pay. 275 - 40 is 235. That's $235 for the bike at Cycle Center. I'll write the prices of the bikes out to make it easier to read.
Mike's Bikes: $225
Cycle Center: $235
Okay. so when you look at the prices for the mountain bikes, you see that the bike at Mike's Bikes is $10 cheaper than the bike at Cycle Center. Dante should purchase his mountain bike at Mike's Bikes, because he will pay less money there. The Cycle Center does give $40 back, but Mike's Bikes has the bike that costs less. 225 < 235.
Answer:
<h2>Net proceed= s-0.98nd-11</h2>
Step-by-step explanation:
Given that the shares cost $d
n shares will be =$dn
paid 2% commission to her broker= (2/100)*nd= 0.02nd
sold the share for $s
paid a fee of $11
Her net proceeds algebraically will be
Net proceed= s-nd-11-0.02nd
collect like terms
Net proceed= s-(nd-0.02nd)-11
Net proceed= s-0.98nd-11
I'll help but information is missing, you need to have the cost and the number of pencil she will buy
Answer:
To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic
1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation
We simplify and check the number of real roots with the quadratic formula, 
for quadratic equations the form 0 = a·x² - b·x + c
Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.
Step-by-step explanation:
