Answer:
It is not possible to draw a triangle with given measurements of 3.5, 3.5, and 9.
Step-by-step explanation:
<em><u>Scalene Triangle</u></em> - All 3 sides have different lengths.
<em><u>I</u></em><em><u>s</u></em><em><u>osceles</u></em><em><u> </u></em><em><u>Triangle</u></em> - 2 sides have equal lengths.
<em><u>Equilateral</u></em><em><u> </u></em><em><u>Triangle</u></em> - All 3 sides have equal lengths.
You must be thinking that it would be Isosceles triangle, but it is not. The measurements you gave is 3.5, 3.5, and 9. Grab a piece of paper, ruler, and a pencil. First draw the length of 9 cm with your pencil and ruler (let us pretend that the measurements are in cm). Then draw 3.5 cm by placing your ruler on the end/start of your 9cm line that you drew before. Then, once again draw a 3.5 cm on the other end of the 9cm line. You will see something like the picture above. You can see that the two sides of the triangle are not intersecting on the top. This means that the triangle formation cannot be made by the given measurements of 3.5, 3.5, and 9.
I hope you understand my answer and this is an easy way to find if, from the given measurements, a triangle is able to be drawn. Thank you !!
Answer:
13 (c)
Step-by-step explanation:
Graph the equation 7000(1-0.19)^x and then the inequality y<500, the point of intersection should be 12.524, so the answer will be rounded up to 13 i think
X - 9 + 2wx = y Add 9 to both sides
x + 2wx = y + 9 Factor out the x
x (1 + 2w) = y + 9 Divide both sides by (1 + 2w)
x = (y + 9) / (1 + 2w)
3x2(4x<span> – 3) + 1(4</span>x<span> – 3) </span>
In order to find the sum of the given rational expressions above, here are the steps.
Firstly, you need to find the LCM of the least common denominator.
So it would look like this:
<span>3x-1 + 3x (3x-1)(x-1) + (2x)(3x)
------ ------- = ---------------------------
2x x-1 2x(x-1)
3x^2-4x+1+6x^2
----------------------
2x(x-1)
And the final result would be this:
9x^2-4x+1
--------------
2x(x-1)
</span>9x^2-4x+1
--------------
2x^2-2x
<span>
Hope that this is the answer that you are looking for.
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