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2 years ago

If the relative frequency of a train being late is 0.15 how often could you expect the train to be late in 100 days?

Mathematics

1 answer:

neonofarm [45]2 years ago

7 0

(100)= 0.25*100=15 times.

<span>SO, the train will be late 15 times in 100 days.

Hope i helped:P </span>

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Which represents the solution(s) of the graphed system of equations, y = x2 + x – 2 and y = 2x – 2? (–2, 0) and (0, 1) (0, –2) a

Luda [366]

ANSWER

$(0,-2), (1,0)$

EXPLANATION

The first equation is

$y = {x}^{2} + x - 2$

The second equation is

$y = 2x - 2$

We equate both equations to get,

${x}^{2} + x - 2 = 2x - 2$

${x}^{2} + x - 2x - 2 + 2 = 0$

Simplify

${x}^{2} - x = 0$

Factor

$x(x - 1) = 0$

Either

$x = 0$

$x - 1 = 0$

$x = 1$

Put x=0 or x=1 into the second equation to get,

$y = 2(0) - 2 = - 2$

$y = 2(1) - 2 = 0$

Therefore the solutions are;

$(0,-2), (1,0)$

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2 years ago

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Volume =160.875m, length =6.5m, height =5.5m, breadth =?

mestny [16]

Answer:

b = 4.5 m

Step-by-step explanation:

Since we have 2 sides of the shape and the total volume, we can easily find the measurement of the third side which is the breadth by:

volume = 160.875

v = l×h×b

160.875m=(6.5m)×(5.5m)×b

160.875m=35.75b

b = 4.5 m

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2 years ago

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Which composite function can be used to find the

eduard

Given:

The mass function is:

$m(v)=4.5v$

where v is the volume in cubic centimeters.

The force function is:

$F(m)=800m$

To find:

The composite function can be used to find the force of the object based on its volume.

Solution:

The composite function can be used to find the force of the object based on its volume is:

$F(m(v))=F(4.5v)$ $[\because m(v)=4.5v]$

$F(m(v))=800(4.5v)$ $[\because F(m)=800m]$

$F(m(v))=3600v$

Therefore, the correct option is D.

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2 years ago

An electronics store chain sells headphones. The company is about to introduce a new headphone model that is expected to sell ve

Luda [366]

Answer:

hey did you find the answer

Step-by-step explanation:

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2 years ago

Suppose you select a sample of 12 individuals and find that 10 of them do not exercise regularly. Assuming that the Surveillance

Leto [7]

Answer:

a. mean = 6.96 , standard deviation = 1.71 b. 0.0641

Step-by-step explanation:

Here is the complete question

According to the Behavioural Risk Factor Surveillance System, 58% of all Americans adhere to a sedentary lifestyle (sedentary means does not exercise).

a. If you selected repeated samples of 12 from the U.S. population, what would be the mean number of individuals per sample who do not exercise regularly? What would be the standard deviation?

b. Suppose you select a sample of 12 individuals and find that 10 of them do not exercise regularly. Assuming that the Surveillance System is correct, what is the probability that you would have obtained results as bad or worse than expected?

<em>Solution</em>

a. Since we can only have two types of outcomes, that is, those who exercise and those who do not exercise, the problem follows a binomial distribution.

Since the probability of those who do not exercise, p = 58 % = 0.58,

the mean of the binomial distribution μ = np where n = sample number = 12

So, μ = 12 × 0.58 = 6.96

The standard deviation of a binomial distribution σ = √(npq) where q = probability that people exercise = 1 - p = 1 - 0.58 = 0.42

So, σ = √(12 × 0.58 × 0.42) = √2.9232 = 1.71

b. To find the worst case, we consider the probability that at best, two exercise. Since two exercise, the probability that at best two exercise is ¹²C₂q²p¹⁰ + ¹²C₁qp¹¹ + ¹²C₀q⁰p¹²

= (12 × 11/2)(0.42)²(0.58)¹⁰ + 12(0.42)(0.58)¹¹ + 1 × (0.42)⁰(0.58)¹²

= 0.05 + 0.0126 + 0.00145

= 0.06405

≅ 0.0641

6 0

2 years ago