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2 years ago

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In a survey of a town, 56% of residents own a car, 21% of residents now a truck, and 4% of residents own both a car and a truck.

What is the conditional probability that a person also owns a truck, given that they own car? Round to the nearest whole percent.

2 answers:

babunello [35]2 years ago

8 0

4.6 rounded to whole number would be 5%

Iteru [2.4K]2 years ago

5 0

Answer:

$P(A given B)=0.190$

Step-by-step explanation:

It is given that In a survey of a town, 56% of residents own a car, that is P(A)=0.56

21% of residents now a truck, that is P(B)=0.21

and 4% of residents own both a car and a truck that is P(A∩B)=0.04

Now, the conditional probability that a person also owns a truck, given that they own car is:

$P(A given B)=\frac{P(A{\cap}B)}{P(B)}$

$P(A given B)=\frac{0.04}{0.21}$

$P(A given B)=0.190$

Thus, the conditional probability that a person also owns a truck, given that they own car is 0.190.

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One in a hundred million people is a genius. If they are a genius, the probability that the person is acting extremely quirky is

Mila [183]

Answer:

The correct option is E) About 1 in a million.

Step-by-step explanation:

Consider the provided information.

It is given that one in a hundred million people is a genius.

Let G represents the Genius and Q represents the quirky.

We need to find the probability that someone is acting quirky- what is the probability that they are a genius.

The probability that person is quirky is: $P(Q)=0.999\cdot0.00000001+0.01\cdot0.99999999$

The probability of $P(Q\cap G)=0.999\cdot0.00000001$

Hence, the required probability is:

$P(G|Q)=\frac{P(Q\cap G)}{P(Q)}$

$P(G|Q)=\frac{0.999\cdot0.00000001}{0.999\cdot0.00000001+0.01\cdot0.99999999}$

$P(G|Q)\approx 9.98999\times10^{-7}$

Which is near about 1 in a million.

Hence, the correct option is E) About 1 in a million.

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2 years ago

Elliot collects miniature toy cars. He wants to fill 4 display cases.each display case holds 15 cars. He has 28 cars now, and he

baherus [9]

Answer:

Elliot has to wait 11 months before he has enough cars

Step-by-step explanation:

Elliot has 4 display cases with each case being able to hold 15 cars. Thus we know

total # of cars Elliot can place in his display case = 4 * 15 = 60 cars

From this, we can figure out how many more cars Elliot needs by subtracting the amount of cars he already has

# of cars Elliot needs = 60 - 28 = 32 cars

Now to find the number of months Elliot needs, we divide by how many he can buy each month

# of months Elliot needs to save up for = 32 / 3 = 10 2/3

Assuming Elliot does not get his allowance until the end of the month, we will have to round the number of months up to the nearest integer, 11

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2 years ago

A triangle has interior angles measuring 36° and 112°. Which triangles are similar to this triangle? Select True or False for ea

morpeh [17]

Hi there!

Since the interior measures of triangles added up always equals 180 degrees, the other interior angle of the triangle must be 32 degrees.

180 - 112 - 36 = 32

So, any triangle with interior measures that measure any angles of 36, 112, and 32 degrees are similar.

<span>triangle with interior angles measuring 36° and 32° - true
triangle with interior angles measuring 36° and 148° - false
triangle with interior angles measuring 32° and 112° - true
triangle with interior angles measuring 112° and 148 - </span>false

Hope this helps!

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2 years ago

Read 2 more answers

Answer Please???? Finn is baking cakes for a party. The number of cups of sugar Finn needs is proportional to the number of cake

Natali [406]

Answer:

Hello there!

The answer to your question is :

<em>C: Finn needs 6 cups of sugar for 4 cakes.</em>

<em>D: Finn needs 1 1/2 cups of sugar for 1 cak</em>e.

Step-by-step explanation:

The graph clearly shows ( sides cups of sugar) (bottom number of cakes)

For sugar you need 6 cups to make 4 cakes

For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake

Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)

This is the confirmed answer I took the quiz and got 100%

Hopes this helps you!

~Darlington

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2 years ago

In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

b

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

c

The probability, $P =0.0002$

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

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2 years ago