The vertex of this parabola is at (-2,-3). When the x-value is -1, the y-value is -5. What is the coefficient of the squared exp
1 answer:
Answer:
Option C is correct
Step-by-step explanation:
Given: vertex of this parabola is at (-2,-3)
To find: coefficient of the squared expression in the parabola’s equation if the x-value is -1, the y-value is -5
Solution:
The equation of parabola is of the form
Here, a is the coefficient of the squared expression in the parabola’s equation.
Put
So, the coefficient of the squared expression in the parabola’s equation is
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Answer:
Step-by-step explanation:
Given
Company Produces and sells 211600 boxes of T-shirt each year
Fixed cost =$ 400
Additional cost = $ 3 per box
storage cost =$ 2
let x be the no of production run
therefore
Holding cost per year
yearly ordering cost
Total cost C(x)
differentiate C(x) w.r.t to x we get
Put to get max/min value
therefore 46 runs must be performed
Answer:
a) n(none) = 25
b) n(PE but not Bio) = 25
c) n(ENG but not both BIO and PE) = 55
d) n(students that did not take Eng or Bio) = 40
e) P( Students did not take exactly two subjects) = 0.65
Step-by-step explanation:
From the Venn diagram drawn:
a) Number of students that took none
n(Freshmen) = 135
n(all three) = 5
n (PE and Bio) = 10
n(PE and Eng) = 15
n(Bio and Eng) = 7
n (PE and Bio only) = 10 - 5 = 5
n(PE and Eng only) = 15 - 5 = 10
n(Bio and Eng only) = 7 - 5 = 2
n(PE only) = 35 - 5 - 5 - 10 = 15
n(Bio only) = 42 - 5 - 5 - 2 = 30
n(Eng only) = 60 - 10 - 5 -2 = 43
n(Freshmen) = n(PE only) + n(Bio only) + n(Eng only) + n(PE and Bio only) + n(PE and Eng only) + n(Bio and Eng only) + n(all three) + n(none)
135 = 15 + 30 + 43 + 5 + 10 + 2 + 5 + n(none)
135 = 110 + n(none)
n(none) = 135 - 110
n(none) = 25
b)Number of students that too PE but not Bio
n(PE but not bio)= n(PE only) + n(PE and Eng only)
n(PE but not Bio) = 15 + 10
n(PE but not Bio) = 25
c) Number of students that took ENG but not both BIO and PE
n(ENG but not both BIO and PE) = n(Eng only) + n(Eng and Bio only) + n(Eng and PE only) = 43 + 2 + 10
n(ENG but not both BIO and PE) = 55
d) Number of students that did not take ENG or BIO
n( students that did not take Eng or Bio) = n(PE only) + n(none)
n(students that did not take Eng or Bio) = 15 + 25
n(students that did not take Eng or Bio) = 40
e) Probability that a randomly-chosen student from this group did not take exactly two subjects
n( Students that did not take exactly two subjects) = n(PE only) + n(Bio only) + n(Eng only)
n( Students that did not take exactly two subjects) = 15 + 30 + 43
n( Students that did not take exactly two subjects) = 88
P( Students did not take exactly two subjects) = 88/135
P( Students did not take exactly two subjects) = 0.65
Answer:
- g(x) = 1.1f(x + 1)
Step-by-step explanation:
g(x) is the translation of the parent function f(x) to left by 1 unit and slightly stretched vertically.
<u>g(x) is:</u>
- f(x) = 1.1f(x + 1)
<em>See attached with both graphs included</em>
