Answer:
<u>0.9524</u>
Step-by-step explanation:
<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>
<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>
<em />
<u>Solution:</u>
This is conditional probability.
Given:
- Probability train arrive on time and leave on time = 0.8
-
Probability train arrive on time = 0.84
-
Probability train leave on time = 0.86
Now, according to conditional probability formula, we can write:
= P(arrive ∩ leave) / P(arrive)
Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"
and
P(arrive) means probability arriving on time given as 0.84, so:
0.8/0.84 = <u>0.9524</u>
<u></u>
<u>This is the answer.</u>
Answer:
positive 2 digit nos range from 10 to 99 that consists of 90 population size the number of 2 digit nubers that are a multiple of 6 is: 15 listed as ... the number of 2 digit nubers that are a multiple of 6 is: 15 ... P(two digit multiple of 6) = 15/90 = 1/6
Step-by-step explanation:
Answer:
Step-by-step explanation:
a)
- p = Total Number of Defects / Sample Size x Number of Samples
- z = Number of standard deviation = 3
- σ = Standard deviation of sampling distribution
- σ = p (1- p) / n = 0.0336 (1- 0.0336) / 300 = 0.0336 x 0.9664 / 300 = 0.0104
- Here, n = number of observations in each sample
- UCL = p+zσ = 0.0336 + 3(0.0104) = 0.0336 + 0.0312 = 0.0648 = 0.065
- LCL = p-zσ = 0.0336 - 0.0312 = 0.0024 = 0.002
b) Hence, Lower control limit cannot be a negative number as percent defective cannot be a negative number. As such, No. Percent of defective records cannot be a negative number.
Answer:3.9
Step-by-step explanation:
you have to add the decimal to the exponent
