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Nikitich [7]
2 years ago
7

In solving a jigsaw puzzle, a move consists of joining two clusters, including clusters of just one piece. What is the minimum n

umber of moves required to complete a two-thousand piece jigsaw puzzle that is separated into individual pieces?
Mathematics
2 answers:
Furkat [3]2 years ago
7 0

Answer:

1999 moves are required.

Step-by-step explanation:

Given is - In solving a jigsaw puzzle, a move consists of joining two clusters, including clusters of just one piece.

This means exactly n-1 moves are required to solve a jigsaw puzzle with n pieces.

Here, n = 2000

So, moves will be = 2000-1=1999

Hence. 1999 moves are needed to solve the puzzle.

ad-work [718]2 years ago
3 0
Solution: As always, try to find a way of looking at the problem that makes the solution simple. In this problem, regardless of the current state of the puzzle, a move consists of combining two clusters into a single cluster. Therefore every move reduces the number of clusters by 1. Since we begin with 2000 clusters (the single pieces) and end with 1 cluster, we need \[2000-1=\boxed{1999}\] moves to complete the puzzle.
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Step-by-step explanation:

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Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

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Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

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⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

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