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Kobotan [32]
2 years ago
5

An elevator ascends at a rate of 29.6 feet per second. If a building is 1,450 feet tall, about how long would it take for the el

evator to travel from the ground floor to the roof
Mathematics
2 answers:
nadezda [96]2 years ago
8 0
1,450/29.6= 48.986 seconds
It would take 49 seconds for the elevator to travel from the ground floor to the roof.
lianna [129]2 years ago
7 0

Answer:

49 seconds.

Step-by-step explanation:

We have been given that an elevator ascends at a rate of 29.6 feet per second. A building is 1,450 feet tall. We are asked to find the time it will take for the elevator to travel from the ground floor to the roof.

To find the time taken by elevator to reach the top of the building, we will use rate formula.

\text{Time}=\frac{\text{Distance}}{\text{Rate}}

\text{Time}=\frac{\text{1450 ft}}{\frac{\text{29.6 feet}}{\text{second}}}

\text{Time}=\frac{\text{1450 ft}}{\text{29.6 feet}}\times\text{second}

\text{Time}=48.986486\times\text{second}

\text{Time}\approx 49\text{ seconds}

Therefore, it will take approximately 49 seconds for the elevator to travel from the ground floor to the roof.

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Answer:

a) Proportion of the sampled angles are at least 30° = 0.144

b) Proportion of sampled angles between 10 and 25 = 0.415

Step-by-step explanation:

Class Relative Frequency

0-<5                 0.176

5-<10                0.169

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15-<20          0.139

20-<30          0.193

30-<40          0.075

40-<60          0.04

60-<90          0.029

A) Proportion of the sampled angles which are at least 30° can be calculated by adding the relative frequencies which are greater than 30. This will include the classes 30-<40, 40-<60 and 60-<90, So,

proportion of the sampled angles are at least 30° = 0.075 + 0.04 + 0.029

proportion of the sampled angles are at least 30° = 0.144

B) For the proportion of angles between 10 and 25, we need to consider the classes 10-<15, 15-<20 and 20-<30. Since we are interested in the angles up till 25 degrees, we need to divide the relative frequency of the class 20-<30 by 2 because 25 lies in the middle of this class. So,

Proportion of sampled angles between 10 and 25 = 0.179 + 0.139 + (0.193/2)

Proportion of sampled angles between 10 and 25 = 0.415

C) For constructing the histogram, you need to plot the relative frequencies on the y axis and the classes on the x-axis by choosing a suitable scale for both the axes. I have plotted the graph on paint but its a bit untidy. I am attaching the graph as a snippet here so that you can have an idea of the heights.  

By looking at the heights of the classes, we can say that <u>The distribution of misorientation angles is heavily positively skewed</u> because there is a tail at the positive side of the graph. The graph is also unimodal since there is only one highest peak present.

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