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Katen [24]
2 years ago
12

Emma conducted an experiment in which she rolled a six-sided, fair number cube 300 times. How many times would you predict she r

olled a 6?
Mathematics
2 answers:
anygoal [31]2 years ago
7 0
50 because there are 6 sides and 300 roles, if its equal of course. ;)!
Zina [86]2 years ago
4 0

A number cube has six sides. The probability of landing on any of the numbers is equal. The theoretical probability of rolling a 6 is 1/6. I expect a 6 to be rolled (1/6)(300), or 50 of 300 times

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The diagonals of the figure below represent the support beams for a patio covering.
Bas_tet [7]

Answer: B 5 and 5 square root 3

Step-by-step explanation:

3 0
2 years ago
Darcie wants to crochet a minimum of 3 blankets. Darcie crochets at a rate of 1/15 of a blanket a day. She has 60 days until she
NNADVOKAT [17]

Answer:

The inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal can be given as:

s\leq 15

Step-by-step explanation:

The complete question is:

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15 of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways. Write an inequality to determine the number of days, s, Darcie can skip crocheting and still meet her goal.

Solution:

Given:

Darcie wants to crochet a minimum of 3 blankets to donate.

Rate at which she crochet = \frac{1}{15} of a blanket per day.

Maximum number of days she has = 60.

To find the number of days Dancie can skip out of 60 days and still reach her goal.

Let s represent the number of days she can skip.

Number of days left to crochet = (60-s) days

At rate of  \frac{1}{15} of a blanket per day, number of blankets Dancie can corchet in (60-s) days can be given as :

⇒ \frac{1}{15}(60-s)

Simplifying using distribution.

⇒ (\frac{1}{15}.60)-(\frac{1}{15}.s)

⇒ 4-\frac{s}{15}

Dancie needs to crochet a minimum of 3 blankets to reach her goal.

Thus, the inequality can be given as:

4-\frac{s}{15}\geq 3

Solving the inequality for s

Subtracting 4 both sides.

4-4-\frac{s}{15}\geq 3-4

-\frac{s}{15}\geq -1

Multiplying both sides by -15.

-15(-\frac{s}{15})\leq -15(-1) [On multiplying by a negative number the sign of inequality reverse]

∴ s\leq 15

Thus, Dancie can skip a maximum of 15 days.

5 0
2 years ago
Ariel snowboarded down a mountain that has a vertical height of 1,200 feet. She traveled a distance of 2,400 feet from the top o
KIM [24]
For this case what you should do is use the following trigonometric relationship
 senx = (1200) / (2400)
 senx = 0.5
 Clearing the angle we have
 x = ASIN (0.5)
 x = 30
 Answer:
 The angle of elevation from the base to the top of the mountain is 30 °
6 0
2 years ago
The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If
frutty [35]
For this case we have the following equation:
 w = 0.9* \sqrt{E}
 Where,
 w: The weight of a spring in pounds
 E: the energy stored by the spring in joules.
 Substituting values we have:
 w = 0.9* \sqrt{12}
 Making the corresponding calculation:
 w=3.12
 Answer:
 
the approximate weight of the spring in pounds is:
 
w=3.12
4 0
2 years ago
Read 2 more answers
What is a3 in an arithmetic sequence in which a10=41 and a15=61
USPshnik [31]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

thus

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and surely you know how much that is.
8 0
2 years ago
Read 2 more answers
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