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topjm [15]
2 years ago
5

64-144a+108a^2-27a^3​

Mathematics
1 answer:
solmaris [256]2 years ago
3 0

the answer for this question is 64-144a+108a^2-27a^3

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A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would
miv72 [106K]
The solution for this problem would be:
Given that there is 99.999%.

Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n

Therefore, (1-p) ^n = 0.00001


a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer


1-(1-.97)^3= 0.99999 + 0.0001 = 1


b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer


1-(1-.88)^3= 0.99 + 0.0001 = approx 1
4 0
2 years ago
Solve for the indicated variable u=x-k, for x
Papessa [141]
X = u + k
hope this helps & hope I get the brainliest answer
6 0
2 years ago
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Evaluate. 58−(14)2=58-142= ________
nasty-shy [4]

For this case we have the following expression:

58- (14) ^ 2

The first step is to solve the quadratic term.

We have then:

58- (14) ^ 2 = 58-196

Then, the second step is to subtract both resulting numbers:

58- (14) ^ 2 = -138

We observe that the result obtained is a negative number.

Answer:

The result of the expression is given by:

58- (14) ^ 2 = -138

7 0
2 years ago
For positive acute angles
insens350 [35]

9514 1404 393

Answer:

  77/85

Step-by-step explanation:

<u>Given</u>:

  cos(A) = 4/5

  sin(B) = 15/17

<u>Find</u>:

  cos(A-B)

<u>Solution</u>:

From your knowledge of Pythagorean triples, you know that one of them is (3, 4, 5) and another is (8, 15, 17). Using your imagination, or by drawing the triangles, you can determine the needed trig functions to be ...

  sin(A) = 3/5

  cos(B) = 8/17

__

Alternatively, you can use the Pythagorean identity to find ...

  sin(A) = √(1 -cos²(A)) = √(1 -(4/5)²) = √(9/25) = 3/5

  cos(B) = √(1 -sin²(B)) = √(1 -(15/17)²) = √(64/289) = 8/17

__

Then application of the angle difference formula is straightforward.

  cos(A -B) = cos(A)cos(B) +sin(A)sin(B)

  cos(A -B) = (4/5)(8/17) +(3/5)(15/17) = (32 +45)/85

  cos(A -B) = 77/85

_____

Some graphing calculators can express the result ...

  cos(arccos(4/5) -arcsin(15/17)) ≈ 0.90588235294

  ... as the fraction 77/85

5 0
2 years ago
On a coordinate plane, 2 triangles are shown. Triangle A B C has points (negative 1, 1), (negative 4, 1) and (negative 1, 5). Tr
Reptile [31]

Answer:

The figures are congruent because a 270° rotation about the origin and then a reflection over the x-axis will map ΔABC onto ΔLMN.

8 0
2 years ago
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