What is a27 of the sequence 15,10,5,…?
1 answer:
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Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder=
Considering, π= 3.14
⇒ lateral surface area of cylinder=
⇒ lateral surface area of cylinder=
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution=
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
Answer:
The coordinates of the mid-point of JL are (-5 , 2)
Step-by-step explanation:
If point (x , y) is the mid-point of a segment whose end-points are and
, then
and
∵ JL is a segment
∵ The coordinates of J are (-6 , 1)
∴ = -6 and
= 1
∵ The coordinates of L are (-4 , 3)
∴ = -4 and
= 3
Lets use the rule above to find the mid-point of JL
∵
∴ x = -5
∴ The x-coordinate of the mid-point is -5
∵
∴ y = 2
∴ The y-coordinate of the mid-point is 2
∴ The coordinates of the mid-point of JL are (-5 , 2)