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ValentinkaMS [17]
2 years ago
6

Which shows the image of quadrilateral ABCD after the transformation Ro, 90?

Mathematics
1 answer:
Andrew [12]2 years ago
7 0

Answer:

The quadrilateral would be in the quadrant 4, A (1,0) B (0,1) C(-2,3) D(-3,2)

Step-by-step explanation:

The A point stays on the X-axis because it is on the axis, and everything else rotates 90 degrees

Hope this helps

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Tyler reads 2/15 of a book on Monday, 1/3 of it on tuesday, 2/9 of it on Wednesday, and 3/4 of the remainder on thus day. If he
kykrilka [37]

The number of pages in the book is 180

<u>Explanation:</u>

The first thing we should do is to convert these fractions to percentage

Monday = \frac{2}{15} X 100 = 13.33\\\\Tuesday = \frac{1}{3} X 100 = 33.33%\\\\\\Wednesday = \frac{2}{9} X 100 = 22.22%\\\\\\\\

3/4 of the remainder on thursday:

Thursday: (100 - (13.33 + 33.33 + 22.22) * (3/4) = 23.33%

he still has 14 pages left to read on friday

Friday:  [100 - (13.33 + 33.33 + 22.22) ] - 23.33 = 7.77%

Which means that 14 pages represent 7.77% of the book.

Therefore the number of pages of the book is given by:

=\frac{100}{7.77} X 14\\\\= 180

Therefore, number of pages in the book is 180

4 0
1 year ago
A square has a side of 3x - 4 what is the area of the Square in terms of x?
Doss [256]

Answer:

9x2−24x+16

Hope this helps!

Step-by-step explanation:

The formula for a square is side times side since every side is of equal length. Because we are leaving the answer in terms of x you just multiply 3x-4 by 3x-4 and simplify and you get 9x2−24x+16

Please mark as brainliest :)

3 0
1 year ago
The graph shows the solution to the initial value problem y'(t)=mt, y(t0)= -4
Charra [1.4K]
y'(t)=mt&#10;\\&#10;\\ y=\int {mt} \, dt=m \int{t} \,dt=m \frac{t^2}{2} +C \\ \\y= \frac{mt^2}{2}+C

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.

y=at^2+b&#10;\\&#10;\\3=a\times 2^2-2&#10;\\&#10;\\3=4a-2&#10;\\&#10;\\5=4a&#10;\\&#10;\\a= \frac{5}{4} &#10;\\&#10;\\y=\frac{5}{4} t^2-2 \\ \\y= \frac{m}{2} t^2+C&#10;\\ \\  \frac{m}{2} = \frac{5}{4} &#10;\\&#10;\\m= \frac{5}{2} &#10;\\&#10;\\C=-2&#10;\\&#10;\\y(t_0)=-4&#10;\\&#10;\\-4= \frac{5}{4} t_0^2-2&#10;\\&#10;\\ -2= \frac{5}{4} t_0^2&#10;\\&#10;\\ t_0^2=- \frac{8}{5} &#10;\\&#10;\\t_0=\pm \sqrt{- \frac{8}{5} }



3 0
2 years ago
Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot
kogti [31]

Answer:

x=\frac{30}{7}

Step-by-step explanation:

We have been given an equation \frac{2}{3}x=-\frac{1}{2}x+5. We are asked to solve our given equation.

First of all, we will add \frac{1}{2}x on both sides of equation to separate x variable on one side of equation.

\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5

\frac{2}{3}x+\frac{1}{2}x=5

Now, we will make a common denominator.

\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5

\frac{4}{6}x+\frac{3}{6}x=5

Add numerators:

\frac{4+3}{6}x=5

\frac{7}{6}x=5

Upon multiply both sides of our equation by \frac{6}{7}, we will get:

\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}

x=\frac{5*6}{7}

x=\frac{30}{7}

Therefore, the solution for our given equation is x=\frac{30}{7}.

5 0
1 year ago
Read 2 more answers
The closing price (in dollars) per share of stock of tempco electronics on the tth day it was traded is approximated by p(t) = 2
Vaselesa [24]

solution:

The closing price (in dollars) per share of stock of Tempco Electronics on the tth day it was  

traded is approximated by  

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15 (0 ≤ t ≤ 24)  

where t = 0 corresponds to the time the stock was first listed on a major stock exchange.  

What was the rate of change of the stock's price at the close of the 15th day of trading?  

P'(t) = 12(cos πt/30) - 6 (cos πt/15) + 4(cos πt/10) - 3(cos 2πt/15)  

t = 15  

P'(t) = 12(cos 15π/30) - 6 (cos 15π/15) + 4(cos 15π/10) - 3(cos 30π/15)  

P'(t) = 12(cos π/2) - 6 (cos π) + 4(cos 3π/2) - 3(cos 2π)  

P'(t) = 12(0) - 6(-1) + 4(0) - 3(1) = 6 - 3  

P'(t) = $3 per day RATE OF CHANGE  

the closing price on that day

P(t) = 20 + 12 sin πt/30 − 6 sin πt/15 + 4 sin πt/10 − 3 sin 2πt/15  

t = 15  

P(t) = 20 + 12 sin 15π/30 − 6 sin 15π/15 + 4 sin 15π/10 − 3 sin 30πt/15  

P(t) = 20 + 12 sin π/2 − 6 sin π + 4 sin 3π/2 − 3 sin 2π  

P(t) = 20 + 12(1) − 6(0) + 4(-1) − 3(0) = 20 + 12 - 0 - 4 - 0 = 20 + 12 - 4  

P(t) = $28 per share close price



4 0
1 year ago
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