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1 year ago

30 points!!! will mark you brainliest!!!

Mathematics

2 answers:

Alexxandr [17]1 year ago

7 0

Whenever you're asked to find the best prediction based on the graph, you always use the line of best fit (the black line) that is determined from your data points.

Since 202cm isn't on your graph, you will need to write an equation for your line of best fit and mathematically figure out the arm span. If you look at your graph, notice that for every x value, the y value is equal to it. That makes writing the equation easy. Since x=y, your equation is pretty much just y = x.

Your x value that you need to plug in is x=202cm. This is because height is on the x axis and the height you want to find the arm span for is 202cm. Plug x=202 into the equation:
y=x
y=202

The arm span <span>of a player that is 202 cm tall is B) 202cm wide.</span>

Makovka662 [10]1 year ago

7 0

it is going to be B

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Out of five men and five women, we form a committee consisting of four different people. Assuming that each committee of size fo

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1. 10/21

2. 11/42

3. 41/42

4. 2/15

Step-by-step explanation:

Probability defines the ratio of the number of favorable outcomes to the total number of outcomes.

Combination Operations

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$10C4 = \frac{10! }{4! (10-4)!} = \frac{10*9*8*7*6! }{4! 6!} =\frac{10*9*8*7 }{4*3*2*1} =\frac{5040}{24}= 210$

$5C3 = \frac{5! }{3! (5-3)!} = \frac{5*4*3! }{3! 2!} =\frac{5*4 }{2*1} =\frac{20}{2}= 10$

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$8C2 = \frac{8! }{2! (8-2)!} = \frac{8*7*6! }{2! 6!} =\frac{8*7 }{2*1} = 4*7= 28$

$5C4 = \frac{5! }{4! (5-4)!} = \frac{5*4! }{4! 1!} =\frac{5 }{1} = 5$

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1. Probability of forming a committee consisting of two men and two women

= $\frac{5C2 * 5C2}{10C4} =\frac{10*10}{210} =\frac{10}{21}$

2. Probability of forming a committee that has more women than men

(NOTE: Since the committee desired has only 4 members, forming a committee that has more women than men can only be possible if we have 4 women, 0 men or 3 women 1 man)

= $\frac{5C3 * 5C1 + 5C4*5C0}{10C4} = \frac{10 * 5 + 5*1 }{210} = \frac{50 + 5}{210}=\frac{55}{210} = \frac{11}{42}$

3. Probability of forming a committee that has at least one man

(NOTE: at least one man implies the committee must not have all women members )

= $1 - \frac{5C4}{10C4} = 1 - \frac{5}{210} = 1 - \frac{1}{42} = \frac{41}{42}$

4. Probability of forming a committee with both Alice and Bob are members of the committee (NOTE: If Alice and Bob are compulsory member of the committee, there are only two more people to join the committee from the remaining 8 people)

$=\frac{8C2}{10C4} =\frac{28}{210} =\frac{2}{15}$

it be like a coin toss ut a little more complicated. For every toss we have 4 outcomes from 210 possililities

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