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2 years ago

30 points!!! will mark you brainliest!!!

Mathematics

2 answers:

Alexxandr [17]2 years ago

7 0

Whenever you're asked to find the best prediction based on the graph, you always use the line of best fit (the black line) that is determined from your data points.

Since 202cm isn't on your graph, you will need to write an equation for your line of best fit and mathematically figure out the arm span. If you look at your graph, notice that for every x value, the y value is equal to it. That makes writing the equation easy. Since x=y, your equation is pretty much just y = x.

Your x value that you need to plug in is x=202cm. This is because height is on the x axis and the height you want to find the arm span for is 202cm. Plug x=202 into the equation:
y=x
y=202

The arm span <span>of a player that is 202 cm tall is B) 202cm wide.</span>

Makovka662 [10]2 years ago

7 0

it is going to be B

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A cross shaped pattern is made by arranging four identical rectangles around the sides of a square. The area of the square is 36

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Answer:

Area of a square is length * length

Area of a rectangle is length * breadth

In the question, the area of the square is 36

And the area of the rectangle is $1(1/3)$ the area of the square

To find the area of the rectangle, multiply 1(1/3) by the area of the square(36)

Area of rectangle becomes, 1(1/3) * 36 = (4/3) * 36 = 48cm2

To find the perimeter of the shape, we must find the perimeter of the rectangle - perimiter of the square

Since area of square is length * length, the length of the square is 6cm

The breadth of the rectangle is equal to the length of the square, hence, b = 6cm

Since, length * breadth = 48

l * 6 = 48

l = 8

Perimeter of the shape = 4 * perimeter of rectangle - perimter of square

Perimeter of rectangle = 2(l+b)

Perimeter of sqaure = 4l

Our answer = 4 * 2(6+8) - 4(6)

= 4 * 28 - 36

= 88cm

Step-by-step explanation:

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For the first year of his car insurance policy, Tom pays $77 per month. Tom's payments are reduced to $65 per month in the secon

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77/65=1.18
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Shakira went bowling with her friends. She paid $3 to rent shoes and then $4.75 for each game of bowling. If she spent a total o

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A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L

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Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

$P(X=x)=(nCx)p^{x}(1-p)^{n-x}$

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

$nCx=\frac{n!}{x!(n-x)!}$

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

$P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}$

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

$P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}$

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

$P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}$

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

$P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)$

$P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}$

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

$Y1 + Y2 \leq 1$

$Y1 + Y2\leq 1$ when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate $P(Y1+Y2\leq 1)$ we must sume all the probabilities that satisfy the equation :

$P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)$

$P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448$

$P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224$

$P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192$

$P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864$

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The dot plot or histogram will be skewed.

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