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andreev551 [17]
2 years ago
5

Caroline bought 20 shares of stock at 10 ½, and after 10 months the value of the stocks was 11 ¼. If Caroline were to sell all h

er shares of this stock, how much profit would she make? A. $210 B. $10 C. $15 D. $225
Mathematics
1 answer:
OleMash [197]2 years ago
4 0
20 shares at 10 1/2 (or 10.5) = 20 * 10.5 = 210
20 shares at 11 1/4 (or 11.25) = 20 * 11.25 = 225

so the profit made would be : 225 - 210 = $ 15 <==
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Stanley has a collection of seashells. He found 35% of his collection on Florida beaches. If Stanley has 49 seashells from Flori
m_a_m_a [10]

Answer:

The number of seashells he have in his collection all together is <u>140</u>.

Step-by-step explanation:

Given:

Stanley has a collection of seashells. He found 35% of his collection on Florida beaches.

Stanley has 49 seashells from Florida.

Now, to find the number of seashells of his collection altogether.

Let the number of seashells all together be x.

Percentage of seashells found on Florida beaches = 35%.

Number of seashells found on Florida beaches = 49.

Now, to get the number of seashells altogether we put an equation:

35\%\ of\ x=49.

⇒ \frac{35}{100} \times x=49

⇒ 0.35\times x=49

⇒ 0.35x=49

Dividing both sides by 0.35 we get:

⇒ x=140.

Therefore, the number of seashells he have in his collection all together is 140.

4 0
1 year ago
Sherry was in charge of distributing 25 food items
Valentin [98]

Answer:

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Step-by-step explanation:

6 0
1 year ago
5(n+2)-8=2n<br> what s the solution for x??
PIT_PIT [208]
5n+10-8=2n
5n+2=2n
-3n=2
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6 0
2 years ago
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What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 &gt; 15?
pentagon [3]

Step-by-step explanation:

1.

2d + 3 \leqslant  - 11 \\ 2d \leqslant  - 11 - 3 \\ 2d \leqslant  - 14 \\  \frac{2d}{2}  \leqslant  \frac{ - 14}{2}  \\ d \leqslant - 7

2.

3d - 9 > 15 \\ 3d > 15 + 9 \\ 3d > 24 \\  \frac{3d}{3}  >  \frac{24}{3}  \\ d = 8

Welcome

3 0
1 year ago
The rule T1, -4 RO, 180°(x, y) is applied to rectangle KLMN. Which rectangle shows the final image??
fomenos
Let me help you!

Looking at the visual, we can see five figures: KLM, 1, 2, 3, and 4.
Applying t<span>he rule T1, -4 RO, 180°(x, y) to rectangle KLMN - without even solving - just by merely observing, we can say (without a doubt) that the rectangle KLMN will most likely fall in the negative axis.

First rotation: -4 to the left.
Second rotation: -4 to the left.
Last rotation: -4 to the left making the last figure 3. <----- What we are looking for!

Therefore, the rectangle which shows the final image is figure 3 or rectangle 3.</span>
7 0
2 years ago
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