The correct answer according to me is 3=12
Answer:
10 quarters = $2.50
10 nickels = $0.50
that leaves $0.20 for other coins (dimes / pennies)
Step-by-step explanation:
First, suppose she has only quarters and nickels and no other coins. Then if C is the identical number of coins of each type, then 5C + 25C = 320, so 30C = 320 and 3C = 32, but there is no integer solution to this. So she must have at least one other type of coin.
Assume she has only quarters, nickels, and dimes. Then if D is the number of dimes, 5C + 25C + 10D = 320, which means 30C + 10D = 320, or 3C + D = 32. The smallest D can be is 2, leaving 3C = 30 and thus C = 10. So in this scenario she would have 10 quarters, 10 nickels, and two dimes to make $2.50 + $0.50 + $0.20 = $3.20.
This has to be the highest number, because if she had 11 quarters and 11 nickels, that alone would add up to 11(0.25) + 11(0.05) = $3.30, which would already be too much.
Answer:
Ruth's 1931 salary was equivalent to a 2015 salary of $1,247,368.
Step-by-step explanation:
This question can be solved by a rule of three.
Government statistics show a consumer price index of 15.2 for 1931 and 237 for 2015.
This means that $15.2 in 1931 is equivalent to $237 in 2015. So
$15.2 in 1931 - $237 in 2015
$80,000 in 1931 - $x in 2015



Ruth's 1931 salary was equivalent to a 2015 salary of $1,247,368.
Let

be the number of hours that the waitress works in the evening.
We know for our problem that she works

in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>

<span>Since </span>

, we can rewrite our expression:


We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction:

hours.