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love history [14]
2 years ago
11

A portion of a hiking trail slopes upward at about a 6 angle. To the nearest tenth of a foot, what is the value of x, the distan

ce the hiker traveled along the path, if he has traveled a horizontal distance of 120 feet?
Mathematics
1 answer:
Firdavs [7]2 years ago
4 0
The distance covered by the hiker if he traveled a horizontal distance of 120 ft at and angle of 6° will be given by:
cos θ=adjacent/hypotenuse
let the hypotenuse be h, adjacent =120 ft, θ=6°, thus plugging in the values we shall have:
cos 6=120/h
h=120/cos 6
h=120.661 ft
Answer: 120.661 ft
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Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
The cruise boat can carry up to 45 passengers. The company wants to know the minimum number of passengers needed per cruise to c
aksik [14]
Fixed costs:
$350 + $120 + $170 = $640
Variable costs:
x * ( $6.50 + $3.64 ) = x * 10.14
Sales income ( total ):
x * $36.40
FC + FV - Income = 0
640 + 10.14 x - 36.40 x = 0
640 - 26.26 x = 0
26.26 x = 640
x = 640 : 26.26 = 24.37
Answer:
The minimum number of passengers needed per cruise, so that the cruise company can be sure it will make a profit is 25. 
3 0
2 years ago
At the beginning of the business day, a bank's vault held $575,900. By the end of the day, $(3.5 103) had been added to the vaul
Likurg_2 [28]

3.5*10^3=3,500

3,500+ 575,900=579,400

5 0
2 years ago
You are offered the following gamble based on coin flips. If the first heads occurs on the first flip, you get $2. If the first
Andrews [41]

Answer:

infinity

Step-by-step explanation:

a) the expected value of this gamble in dollars is Infinity

i.e

expected value = \frac{1}{2}*2 +  \frac{1}{4}*4 +  \frac{1}{8}*8 + \frac{1}{16}*16 + ... + \to  \infty (infinty) \\

= 1+1+1+1+1 + ... = \infty

b)

When offered, most people say they would pay only less than $10 to play this game.

What are two reasons why people are willing to pay so much less than the expected value?

These people are ready to pay less than $10 to play this game due to the fact that people usually overlook the unlikely event when making decisions. In a bid to that logic, they gamble in order to double their amount of money and the probability that heads may never come is ignored by these people and they may hope for a likely event i.e a head every time they play the game.

Also, the expected value is so humongous that if and only if that the first head appears after a long series of tails which is  very less certain to occur, because mostly people would think that on an average the length of a series of tails ( or heads) is somewhat near 10 or so, but definitely infinity.

3 0
2 years ago
Each year the soccer team, Peterson United, plays 25 games at their stadium. The owner of Peterson United claimed that last year
Mars2501 [29]
Total Attendence = Mean Attendence × No. of Incidents
= 24,500 × 25
= 612,500.
7 0
2 years ago
Read 2 more answers
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