Answer:
n = 0 or 3
Step-by-step explanation:
2n² - 5n + 2
2n² - 4n - n + 2
2n(n - 2) -1(n - 2)
(n - 2)(2n - 1)
Prime number is one which is divisible by itself and 1
n-2 = 1 n = 3
2n-1 = 1 n = 0
The domain of a function is the set of the possible input values of the function. For example: consider the function f(x) = cos x, the domain of the function is the set of possible values of x.
The cosine function takes x values from all real numbers.
Therefore, the domain of the cosine function is a real numbers.
Answer:

Four raised to the one-sixth power
Step-by-step explanation:
We want to simplify: ![\dfrac{\sqrt{4} }{\sqrt[3]{4} }](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%7B4%7D%20%7D%7B%5Csqrt%5B3%5D%7B4%7D%20%7D)
First, we apply the fractional law of indices to each term.
![\text{If } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}](https://tex.z-dn.net/?f=%5Ctext%7BIf%20%20%7D%20a%5E%7B1%2Fx%7D%3D%5Csqrt%5Bx%5D%7Ba%7D%2C%24%20then%3A%5C%5C%5Csqrt%7B4%7D%3D4%5E%7B1%2F2%7D%5C%5C%5Csqrt%5B3%5D%7B4%7D%3D4%5E%7B1%2F3%7D)
We then have:
![\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%7B4%7D%20%7D%7B%5Csqrt%5B3%5D%7B4%7D%20%7D%3D%5Cdfrac%7B4%5E%7B1%2F2%7D%20%7D%7B4%5E%7B1%2F3%7D%20%7D%5C%5C%24Applying%20the%20division%20law%20of%20indices%3A%20%5Cdfrac%7Ba%5Em%20%7D%7Ba%5En%20%7D%3Da%5E%7Bm-n%7D%5C%5C%5Cdfrac%7B4%5E%7B1%2F2%7D%20%7D%7B4%5E%7B1%2F3%7D%20%7D%3D4%5E%7B1%2F2-1%2F3%7D%5C%5C%5C%5C%3D4%5E%7B1%2F6%7D)
The correct option is B.
Answer:
2801 boxes
Step-by-step explanation:
You have 1 red box
You have 7 blue boxes, so far 8 boxes
There are 49 total black boxes (7*7), making 57 total boxes
There are 49*7 = 343 yellow boxes, making 400 boxes
There are 343*7 = 2401 gold boxes, making for a total of 2801 boxes.